Difference between revisions of "Apps-On-Physics/C2/Inclined-Plane/English"

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−
 
−
 
 
{|border=1
 
{|border=1
 
|| '''Time'''
 
|| '''Time'''
Line 8: Line 6:
  
 
'''Title Slide'''
 
'''Title Slide'''
−
|| Welcome to the Spoken Tutorial on''' Inclined Plane.'''
+
|| Welcome to the Spoken Tutorial on '''Inclined Plane'''.
−
|-
+
|-
 
|| '''Slide Number 2 '''
 
|| '''Slide Number 2 '''
  
−
'''Learning objective '''
+
'''Learning objectives'''
 
|| In this tutorial we will demonstrate,  
 
|| In this tutorial we will demonstrate,  
  
−
'''Inclined Plane App'''.
+
'''Inclined Plane App'''
 
|-
 
|-
 
|| '''Slide Number 3'''
 
|| '''Slide Number 3'''
Line 46: Line 44:
  
 
'''Inclined Plane'''
 
'''Inclined Plane'''
−
 
−
 
−
 
 
|| Let us define an inclined plane.
 
|| Let us define an inclined plane.
 
An '''inclined plane''', is a flat supporting surface tilted at an angle.
 
An '''inclined plane''', is a flat supporting surface tilted at an angle.
Line 66: Line 61:
  
 
'''https://www.walter-fendt.de/html5/phen/'''
 
'''https://www.walter-fendt.de/html5/phen/'''
−
 
−
 
  
 
|| Use the given link to download the''' Apps.'''
 
|| Use the given link to download the''' Apps.'''
  
 
'''https://www.walter-fendt.de/html5/phen/'''
 
'''https://www.walter-fendt.de/html5/phen/'''
−
 
  
 
|-
 
|-
Line 78: Line 70:
 
|| I have already downloaded '''Apps on Physics '''to my '''Downloads''' folder.
 
|| I have already downloaded '''Apps on Physics '''to my '''Downloads''' folder.
 
|-
 
|-
−
|| Point to '''html5phen''' folder in the '''Downloads '''folder.
+
|| Point to '''html5phen''' folder in the '''Downloads''' folder.
−
|| After downloading, '''html5phen''' folder appears in the '''Downloads '''folder.
+
|| After downloading, '''html5phen''' folder appears in the '''Downloads''' folder.
 
|-
 
|-
 
||Double click on '''html5phen''' folder.
 
||Double click on '''html5phen''' folder.
 
||Double click on '''html5phen''' folder.
 
||Double click on '''html5phen''' folder.
 
|-
 
|-
−
||Point to Apps in '''java script''' format and '''htm '''format.  
+
||Point to '''Apps''' in '''java script''' format and '''htm''' format.  
 
|| Now double-click on the '''phen '''folder.
 
|| Now double-click on the '''phen '''folder.
  
−
In this folder, we see '''Apps''' in '''java script''' and '''htm '''format.
+
In this folder, we see '''Apps''' in '''java script''' and '''htm''' format.
 
|-
 
|-
 
|| Point to the '''htm''' formats '''Apps'''.
 
|| Point to the '''htm''' formats '''Apps'''.
Line 94: Line 86:
 
|-
 
|-
 
|| Point to''' Inclined Plane Apps'''.
 
|| Point to''' Inclined Plane Apps'''.
−
|| To open''' Inclined Plane''' press '''Ctrl, F''' keys simultaneously.
+
|| To open '''Inclined Plane''' press '''Ctrl, F''' keys simultaneously.
  
 
In the search bar type '''inclined plane'''.
 
In the search bar type '''inclined plane'''.
 
|-
 
|-
 
|| Right click on '''inclinedplane_en.htm''' file.
 
|| Right click on '''inclinedplane_en.htm''' file.
−
 
  
 
Select the option '''Open With Firefox web Browser'''.
 
Select the option '''Open With Firefox web Browser'''.
−
 
  
 
Cursor on the '''App'''.
 
Cursor on the '''App'''.
−
|| Right click on '''inclinedplane_en.htm '''file.
+
|| Right click on '''inclinedplane_en.htm''' file.
−
 
+
−
 
+
−
Select the option '''Open With Firefox web Browser.'''
+
  
 +
Select the option '''Open With Firefox web Browser'''.
  
 
'''Inclined Plane App''' opens in the '''browser'''.
 
'''Inclined Plane App''' opens in the '''browser'''.
Line 122: Line 110:
 
|| '''Reset''' button on the top of the green panel helps to edit values.
 
|| '''Reset''' button on the top of the green panel helps to edit values.
  
−
 
+
The yellow '''Start''' button is a '''toggle button''' for '''Start/Pause''' and '''Resume'''.
−
The yellow '''Start''' button is a''' toggle button''' for''' Start/Pause '''and '''Resume'''.
+
 
|-
 
|-
 
|| Point to the '''Slow motion.'''
 
|| Point to the '''Slow motion.'''
−
|| '''Slow motion '''check-box is used to observe the motion steadily.
+
|| '''Slow motion''' check-box is used to observe the motion steadily.
  
 
|-
 
|-
−
|| Point to '''Springscale '''and '''Force vectors'''
+
|| Point to '''Springscale''' and '''Force vectors'''
−
|| Then we have '''Springscale''' and '''Force vectors '''radio buttons.
+
|| Then we have '''Springscale''' and '''Force vectors''' radio buttons.
  
 
By default '''Springscale''' is selected.
 
By default '''Springscale''' is selected.
 
|-
 
|-
−
|| Click on '''Start '''button.
+
|| Click on '''Start''' button.
−
|| Click on '''Start '''button.
+
|| Click on '''Start''' button.
 
|-
 
|-
 
||Point to the block.
 
||Point to the block.
 
||Notice that a load is pulled by the '''springscale'''.
 
||Notice that a load is pulled by the '''springscale'''.
 
|-
 
|-
−
|| Click on the '''Pause '''button.
+
|| Click on the '''Pause''' button.
−
|| Click on the '''Pause '''button.
+
|| Click on the '''Pause''' button.
 
|-
 
|-
 
|| Click on the radio button of '''Force vectors'''.
 
|| Click on the radio button of '''Force vectors'''.
Line 150: Line 137:
  
 
|-
 
|-
−
|| Point to the white box for '''Angle of inclination''', '''Weight''', '''Coefficient of friction'''.
+
|| Point to the white box for:
 +
 
 +
'''Angle of inclination'''
 +
 
 +
'''Weight'''  
 +
 
 +
'''Coefficient of friction'''.
 
|| We can change the values of:  
 
|| We can change the values of:  
  
−
'''Angle of inclination, Weight'''and '''Coefficient of friction'''
+
'''Angle of inclination''', '''Weight''' and '''Coefficient of friction''' in the white colour boxes.
−
 
+
−
in the white colour boxes.
+
 
|-
 
|-
 
||Highlight the line from the '''App'''.
 
||Highlight the line from the '''App'''.
 
||Note that these values can be changed within certain limits.
 
||Note that these values can be changed within certain limits.
 
|-
 
|-
−
|| Click on '''Reset '''button.
+
|| Click on '''Reset''' button.
 
|| Click on '''Reset''' button.  
 
|| Click on '''Reset''' button.  
 
|-
 
|-
 
|| Show the changes when the values changed to 0 and 90 degrees.
 
|| Show the changes when the values changed to 0 and 90 degrees.
  
−
Change the '''Angle of inclination '''to 45 degrees and press '''Enter.'''
+
Change the '''Angle of inclination''' to 45 degrees and press '''Enter'''.
 
|| Here we can change the '''Angle of inclination''' from 0 degrees to 90 degrees.
 
|| Here we can change the '''Angle of inclination''' from 0 degrees to 90 degrees.
  
−
 
+
Let’s change the '''Angle of inclination''' to 45 degrees and press '''Enter.'''
−
Let’s change the '''Angle of inclination '''to 45 degrees and press '''Enter.'''
+
 
|-
 
|-
−
|| Now click on '''Start '''button.
+
|| Click on '''Start'''button.
 
|| Now click on '''Start''' button.
 
|| Now click on '''Start''' button.
 
|-
 
|-
−
|| When it reaches in the middle of the inclined plane click on '''Pause '''button.
+
||Point to the load >> click on '''Pause''' button.
−
|| When the load reaches the middle of the '''inclined plane''' click on '''Pause '''button.
+
|| When the load reaches the middle of the '''inclined plane '''click on '''Pause''' button.
 
|-
 
|-
 
||Point to the pink vector.
 
||Point to the pink vector.
−
|| Notice that the pink vector shows the force of gravity (mg).
+
|| Notice that the pink vector shows the force of gravity('''mg''').
−
 
+
  
 
It tries to pull the load towards the center of the Earth.
 
It tries to pull the load towards the center of the Earth.
Line 187: Line 176:
 
|-
 
|-
 
||Point to red vector.
 
||Point to red vector.
−
||The red vector is perpendicular to the surface of '''inclined plane'''.
+
||The red vector is perpendicular to the surface of the '''inclined plane'''.
 
|-
 
|-
 
||Point to blue vector and incline plane.
 
||Point to blue vector and incline plane.
 
||The blue vector is parallel to the surface of the '''inclined plane'''.
 
||The blue vector is parallel to the surface of the '''inclined plane'''.
 
|-
 
|-
−
|| In the incline plane point to each angles(inclined plane png file.)
+
|| In the incline plane point to each angles.
  
 
Sum of the interior angle of a triangle is 180 degrees.
 
Sum of the interior angle of a triangle is 180 degrees.
−
|| If '''theta (θ) '''is 45 degrees, then this angle is 90 degrees.
+
|| If '''theta (θ)''' is 45 degrees, then this angle is 90 degrees.
−
 
+
  
 
As it is perpendicular to the surface of the earth.
 
As it is perpendicular to the surface of the earth.
  
−
 
+
From the triangle’s geometry this angle would be '''(90-θ)'''.
−
From the triangle’s geometry this angle would be '''(90-θ). '''
+
 
|-
 
|-
 
|| '''Slide Number 7'''
 
|| '''Slide Number 7'''
  
 
'''Resolution of vectors'''
 
'''Resolution of vectors'''
−
 
−
 
−
 
 
|| To calculate the magnitude of the forces we need to know theta value.
 
|| To calculate the magnitude of the forces we need to know theta value.
−
 
  
 
Now these two lines are parallel and if we assume that this line is a transversal line.
 
Now these two lines are parallel and if we assume that this line is a transversal line.
  
−
Then angle'''(90-θ) '''is equal this angle through interior angle property.
+
Then angle '''(90-θ)''' is equal this angle through interior angle property.
  
−
 
+
Recall that red vector is perpendicular to the inclined plane.  
−
Recall that red vector is perpendicular to inclined plane.  
+
  
 
Here the angle would be 90 degrees.
 
Here the angle would be 90 degrees.
−
 
  
 
Let us assume this angle as '''x'''.
 
Let us assume this angle as '''x'''.
  
−
So '''90 minus theta plus 90 plus x equals to 180'''
+
So 90 minus '''theta''' plus 90 plus '''x''' equals to 180
  
−
Therefore, '''x equals to theta'''
+
Therefore, '''x''' equals to '''theta'''
 
|-
 
|-
 
|| '''Slide Number 8'''
 
|| '''Slide Number 8'''
  
 
'''Resolution of Vectors'''
 
'''Resolution of Vectors'''
−
 
−
 
 
|| Using basic trigonometry we can resolve the parallel and perpendicular components.
 
|| Using basic trigonometry we can resolve the parallel and perpendicular components.
−
 
  
 
Consider this right angle triangle.  
 
Consider this right angle triangle.  
−
 
  
 
Here the blue parallel component is equal to the black line.  
 
Here the blue parallel component is equal to the black line.  
Line 245: Line 222:
  
 
'''Resolution of Vector'''
 
'''Resolution of Vector'''
 +
|| Parallel force is '''Sin theta'''.
  
−
 
+
'''Sin theta''' equals to '''F'''(parallel) upon '''mg'''.
−
|| Parallel force is Sin theta.
+
−
 
+
−
sin theta equals to F(parallel) upon mg.
+
  
 
Let’s rearrange the equation.  
 
Let’s rearrange the equation.  
  
−
F(parallel) equals to mg sin theta.
+
'''F'''(parallel) equals to '''mg sin theta'''.
  
 
Similarly we can resolve the perpendicular component.  
 
Similarly we can resolve the perpendicular component.  
  
−
F(perpendicular) equals to mg cos theta.
+
'''F'''(perpendicular) equals to '''mg cos theta'''.
 
|-
 
|-
 
|| '''Slide Number 10'''
 
|| '''Slide Number 10'''
Line 268: Line 243:
  
 
Calculate the necessary force to pull the mass.  
 
Calculate the necessary force to pull the mass.  
−
||  
+
|| Let us solve this numerical and verify the answers with the ones shown in the '''App'''.
−
 
+
−
Let us solve this numerical and verify the answers with the ones shown in the''' App'''.
+
 
|-
 
|-
 
|| Click on the '''Reset''' button.
 
|| Click on the '''Reset''' button.
Line 286: Line 259:
 
|| Next change the '''Angle of inclination''' to 30 '''degrees''' and press '''Enter'''.
 
|| Next change the '''Angle of inclination''' to 30 '''degrees''' and press '''Enter'''.
 
|-
 
|-
−
|| Now click on '''Start '''button.
+
|| Click on '''Start '''button.
 
|| Now click on '''Start''' button.
 
|| Now click on '''Start''' button.
 
|-
 
|-
−
|| When it reaches in the middle of the incline plane click on '''Pause '''button.
+
|| Point to the load >> click on '''Pause '''button.
−
|| Again click on '''Pause '''button when the load reaches the center of the inclined plane.
+
|| Again click on '''Pause''' button when the load reaches the center of the inclined plane.
 
|-
 
|-
−
|| Point to '''Normal force, Parallel component, and Necessary force.'''
+
|| Point to '''Normal force''', '''Parallel component''' and '''Necessary force'''.
 
||Observe that the''' App''' has calculated the parameters.
 
||Observe that the''' App''' has calculated the parameters.
 
|-
 
|-
Line 316: Line 289:
 
Necessary force = -F||
 
Necessary force = -F||
  
−
||  
+
|| Calculated value of the parallel component is 4.99 '''N''' and that of normal component is 8.65 '''N'''.
−
 
+
−
Calculated value of the parallel component is 4.99 '''N '''and that of normal component is 8.65''' N '''.
+
  
 
And the necessary force is equal to the parallel force but in the opposite direction.
 
And the necessary force is equal to the parallel force but in the opposite direction.
Line 324: Line 295:
 
Let us compare the answers with the ones shown in the '''App'''.
 
Let us compare the answers with the ones shown in the '''App'''.
 
|-
 
|-
−
||Point to values of '''Normal force, Parallel component, and Necessary force'''.
+
||Point to values of '''Normal force''', '''Parallel component''' and '''Necessary force'''.
 
||Observe that the calculated values are comparable to the measured values.
 
||Observe that the calculated values are comparable to the measured values.
 
|-
 
|-
−
||  
+
|| Cursor on the interface.
 
||Let's observe the effect of friction.
 
||Let's observe the effect of friction.
 
|-
 
|-
−
|| Click on the '''Reset''' button
+
|| Click on '''Reset''' button.
−
|| Click on the '''Reset''' button
+
|| Click on the '''Reset''' button.
 
|-
 
|-
 
|| Enter 0.2 in the '''Coefficient of friction''' box.
 
|| Enter 0.2 in the '''Coefficient of friction''' box.
 
|| In the '''Coefficient of friction''' box type 0.5 and press '''Enter'''.
 
|| In the '''Coefficient of friction''' box type 0.5 and press '''Enter'''.
 +
|-th
 +
|| Click on '''Start''' button.
 +
|| Click on the '''Start''' button.
 
|-
 
|-
−
|| Click on the '''Start '''button.
+
|| Point to the load >> click on '''Pause''' button.
−
|| Click on the '''Start '''button.
+
|| When the load reaches the middle of the '''inclined plane''' click on '''Pause''' button.
−
|-
+
−
|| When it reaches in the middle of the incline plane click on '''Pause '''button.
+
−
|| When the load reaches the middle of the '''inclined plane''' click on '''Pause '''button.
+
 
|-
 
|-
 
||Move the cursor on the black vector.
 
||Move the cursor on the black vector.
 
||Notice that a black vector is added to the blue vector.
 
||Notice that a black vector is added to the blue vector.
  
−
This vector represents '''Force of friction.'''
+
This vector represents '''Force of friction'''.
 
|-
 
|-
 
||Point to Force of friction
 
||Point to Force of friction
−
|| In the green panel '''Force of friction '''is measured as 4.3 '''N.'''  
+
|| In the green panel '''Force of friction''' is measured as 4.3 '''N'''.
 
|-
 
|-
 
|| Point to '''Necessary force.'''
 
|| Point to '''Necessary force.'''
−
 
  
 
Move the cursor on the blue and black vector and then point to green vector.  
 
Move the cursor on the blue and black vector and then point to green vector.  
Line 357: Line 327:
  
 
This is because the total necessary force is, sum of the parallel and frictional forces.
 
This is because the total necessary force is, sum of the parallel and frictional forces.
−
|-
+
 
 
|-
 
|-
 
||'''Slide Number 12'''
 
||'''Slide Number 12'''
Line 373: Line 343:
 
||Let us summarise
 
||Let us summarise
 
|-
 
|-
 +
|| '''Slide Number 12'''
  
−
|| '''Slide Number 12'''
 
 
'''Summary'''
 
'''Summary'''
−
 
 
|| Using this '''App''' we have  
 
|| Using this '''App''' we have  
 
* Demonstrated the motion of a load on an inclined plane with constant velocity.
 
* Demonstrated the motion of a load on an inclined plane with constant velocity.
Line 385: Line 354:
 
'''Acknowledgement'''
 
'''Acknowledgement'''
  
−
These Apps are created by Walter-fendt and his team.
+
These Apps are created by Walter-fendt and his team.
  
 
||These Apps are created by Walter-fendt and his team.
 
||These Apps are created by Walter-fendt and his team.
  
 
|-
 
|-
−
||  
+
|| '''Slide Number 14'''
−
 
+
−
'''Slide Number 14'''
+
  
−
'''About Spoken Tutorial project.'''
+
'''About Spoken Tutorial project'''.
 
|| The video at the following link summarizes the Spoken Tutorial project.
 
|| The video at the following link summarizes the Spoken Tutorial project.
  
Line 402: Line 369:
  
 
'''Spoken Tutorial workshops.'''
 
'''Spoken Tutorial workshops.'''
−
 
−
 
 
|| The '''Spoken Tutorial Project '''team,
 
|| The '''Spoken Tutorial Project '''team,
  

Revision as of 11:54, 13 June 2019

Time Narration
Slide Number 1

Title Slide

Welcome to the Spoken Tutorial on Inclined Plane.
Slide Number 2

Learning objectives

In this tutorial we will demonstrate,

Inclined Plane App

Slide Number 3

System Requirements

Here I am using,
  • Ubuntu Linux OS version 16.04
  • Firefox Web Browser version 62.0.3
Slide Number 4

Pre-requisites

https://spoken-tutorial.org

To follow this tutorial, learner should be familiar with Apps on Physics.

For the pre-requisites tutorials please visit this site.

Slide Number 5

Learning Goals

Using this App we will,
  • Demonstrate the motion of a load on an inclined plane with constant velocity.
  • Calculate the resolution of forces.
Slide Number 6

Inclined Plane

Let us define an inclined plane.

An inclined plane, is a flat supporting surface tilted at an angle.

It has one end higher than the other.

It is used for raising or lowering a load.

Use of an inclined plane provides greater mechanical advantage.

Examples of an inclined plane are ramps, slides, stairs, water slides and others.

Slide Number 6

Link for Apps on physics App

https://www.walter-fendt.de/html5/phen/

Use the given link to download the Apps.

https://www.walter-fendt.de/html5/phen/

Point to the file in the downloads folder I have already downloaded Apps on Physics to my Downloads folder.
Point to html5phen folder in the Downloads folder. After downloading, html5phen folder appears in the Downloads folder.
Double click on html5phen folder. Double click on html5phen folder.
Point to Apps in java script format and htm format. Now double-click on the phen folder.

In this folder, we see Apps in java script and htm format.

Point to the htm formats Apps. We will use the Apps with htm file format.
Point to Inclined Plane Apps. To open Inclined Plane press Ctrl, F keys simultaneously.

In the search bar type inclined plane.

Right click on inclinedplane_en.htm file.

Select the option Open With Firefox web Browser.

Cursor on the App.

Right click on inclinedplane_en.htm file.

Select the option Open With Firefox web Browser.

Inclined Plane App opens in the browser.

Cursor on the interface. This is the interface of Inclined plane.
Point to green panel. The green panel shows different parameters that we can change.
Point to Reset and Start button. Reset button on the top of the green panel helps to edit values.

The yellow Start button is a toggle button for Start/Pause and Resume.

Point to the Slow motion. Slow motion check-box is used to observe the motion steadily.
Point to Springscale and Force vectors Then we have Springscale and Force vectors radio buttons.

By default Springscale is selected.

Click on Start button. Click on Start button.
Point to the block. Notice that a load is pulled by the springscale.
Click on the Pause button. Click on the Pause button.
Click on the radio button of Force vectors. Now select Force vectors radio button.
Point to the arrows. Observe that there are five arrows pointing in different directions.
Point to the white box for:

Angle of inclination

Weight

Coefficient of friction.

We can change the values of:

Angle of inclination, Weight and Coefficient of friction in the white colour boxes.

Highlight the line from the App. Note that these values can be changed within certain limits.
Click on Reset button. Click on Reset button.
Show the changes when the values changed to 0 and 90 degrees.

Change the Angle of inclination to 45 degrees and press Enter.

Here we can change the Angle of inclination from 0 degrees to 90 degrees.

Let’s change the Angle of inclination to 45 degrees and press Enter.

Click on Startbutton. Now click on Start button.
Point to the load >> click on Pause button. When the load reaches the middle of the inclined plane click on Pause button.
Point to the pink vector. Notice that the pink vector shows the force of gravity(mg).

It tries to pull the load towards the center of the Earth.

Point to blue and red vectors. The blue and red vectors are the resolution vectors of gravity.
Point to red vector. The red vector is perpendicular to the surface of the inclined plane.
Point to blue vector and incline plane. The blue vector is parallel to the surface of the inclined plane.
In the incline plane point to each angles.

Sum of the interior angle of a triangle is 180 degrees.

If theta (θ) is 45 degrees, then this angle is 90 degrees.

As it is perpendicular to the surface of the earth.

From the triangle’s geometry this angle would be (90-θ).

Slide Number 7

Resolution of vectors

To calculate the magnitude of the forces we need to know theta value.

Now these two lines are parallel and if we assume that this line is a transversal line.

Then angle (90-θ) is equal this angle through interior angle property.

Recall that red vector is perpendicular to the inclined plane.

Here the angle would be 90 degrees.

Let us assume this angle as x.

So 90 minus theta plus 90 plus x equals to 180

Therefore, x equals to theta

Slide Number 8

Resolution of Vectors

Using basic trigonometry we can resolve the parallel and perpendicular components.

Consider this right angle triangle.

Here the blue parallel component is equal to the black line.

Slide Number 9

Resolution of Vector

Parallel force is Sin theta.

Sin theta equals to F(parallel) upon mg.

Let’s rearrange the equation.

F(parallel) equals to mg sin theta.

Similarly we can resolve the perpendicular component.

F(perpendicular) equals to mg cos theta.

Slide Number 10

Numerical

A mass of 1.02 kg rests on a plane that is inclined at an angle of 30 degrees.

From resolution of vectors find parallel and perpendicular components.

Calculate the necessary force to pull the mass.

Let us solve this numerical and verify the answers with the ones shown in the App.
Click on the Reset button. Click on the Reset button to reset the App.
1.02 Kg = 10 N.

Change the weight to 10 N.

In the App change the values according to the numerical.

First let us convert 1.02 Kg into Newton and enter the value in the Weight box.

Change the Angle of inclination to 30 degrees and press Enter. Next change the Angle of inclination to 30 degrees and press Enter.
Click on Start button. Now click on Start button.
Point to the load >> click on Pause button. Again click on Pause button when the load reaches the center of the inclined plane.
Point to Normal force, Parallel component and Necessary force. Observe that the App has calculated the parameters.
Next we will calculate using the formulae.
Slide Number 11

Resolution of Gravity Forces

F||=mg sin θ

= 1.02 x 9.8 x sin 30

= 4.99 N

F⟂= mg cos θ

= 1.02 x 9.8 x cos 30

= 8.65 N

Necessary force = -F||

Calculated value of the parallel component is 4.99 N and that of normal component is 8.65 N.

And the necessary force is equal to the parallel force but in the opposite direction.

Let us compare the answers with the ones shown in the App.

Point to values of Normal force, Parallel component and Necessary force. Observe that the calculated values are comparable to the measured values.
Cursor on the interface. Let's observe the effect of friction.
Click on Reset button. Click on the Reset button.
Enter 0.2 in the Coefficient of friction box. In the Coefficient of friction box type 0.5 and press Enter.
Click on Start button. Click on the Start button.
Point to the load >> click on Pause button. When the load reaches the middle of the inclined plane click on Pause button.
Move the cursor on the black vector. Notice that a black vector is added to the blue vector.

This vector represents Force of friction.

Point to Force of friction In the green panel Force of friction is measured as 4.3 N.
Point to Necessary force.

Move the cursor on the blue and black vector and then point to green vector.

Notice that the Necessary force required to pull the load has changed to 9.3 N.

This is because the total necessary force is, sum of the parallel and frictional forces.

Slide Number 12

Assignment

A load of 0.612 kg rests on a plane that is inclined at an angle of 60 degrees.

From resolution of vectors find parallel and perpendicular components.

Calculate the necessary force to pull the load.

As an assignment solve this numerical and compare your answer with the ones shown in the App.
Let us summarise
Slide Number 12

Summary

Using this App we have
  • Demonstrated the motion of a load on an inclined plane with constant velocity.
  • Calculated the resolution of forces.
Slide Number 13

Acknowledgement

These Apps are created by Walter-fendt and his team.

These Apps are created by Walter-fendt and his team.
Slide Number 14

About Spoken Tutorial project.

The video at the following link summarizes the Spoken Tutorial project.

Please download and watch it.

Slide Number 15

Spoken Tutorial workshops.

The Spoken Tutorial Project team,

conducts workshops using spoken tutorials

and gives certificates on passing online tests.

For more details, please write to us.

Slide Number 16

Forum for specific questions:

Do you have questions in THIS Spoken Tutorial?

Please visit this site.

Choose the minute and second where you have the question.

Explain your question briefly someone from our team will answer them.

Slide Number 17

Acknowledgement

Spoken Tutorial Project is funded by MHRD, Government of India.
This is Himanshi Karwanje from IIT-Bombay.

Thank you for joining.

Contributors and Content Editors

Karwanjehimanshi95, Madhurig, Nancyvarkey

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