Difference between revisions of "Geogebra/C3/Tangents-to-a-circle/English-timed"
From Script | Spoken-Tutorial
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|00:00 | |00:00 | ||
− | |Hello Welcome to this tutorial on | + | |Hello Welcome to this tutorial on '''Tangents to a circle in Geogebra'''. |
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|01:27 | |01:27 | ||
− | |For this tutorial I will use | + | |For this tutorial I will use '''Grid''' layout instead of "Axes",Right Click on the drawing pad. |
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|01:35 | |01:35 | ||
− | |uncheck | + | |uncheck '''Axes''' Select '''Grid''' |
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|01:53 | |01:53 | ||
− | |Let's type value '3' for radius,Click OK | + | |Let's type value '''3''' for radius,Click OK |
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|01:58 | |01:58 | ||
− | |A circle with centre 'A' and radius '3' cm is drawn. | + | |A circle with centre '''A''' and radius '''3''' cm is drawn. |
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|02:04 | |02:04 | ||
− | |Let's 'Move' the point 'A' & see that circle has same radius. | + | |Let's '''Move''' the point '''A''' & see that circle has same radius. |
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|02:09 | |02:09 | ||
− | |Click on the | + | |Click on the '''New point'''tool,Mark a point 'B' outside the circle. |
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|02:15 | |02:15 | ||
− | | "Select Segment between two points" tool.Join points 'A' and 'B'.A Segment AB is drawn. | + | | "Select Segment between two points" tool.Join points '''A''' and '''B'''.A Segment AB is drawn. |
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|02:25 | |02:25 | ||
− | |Select | + | |Select '''Perpendicular Bisector''' tool, Click on the points '''A''' & '''B'''.Perpendicular bisector to segment 'AB' is drawn. |
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|02:37 | |02:37 | ||
− | |Segment 'AB' and Perpendicular bisector intersect at a point,Click on | + | |Segment '''AB''' and Perpendicular bisector intersect at a point,Click on '''Intersect two objects''' tool. |
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|02:44 | |02:44 | ||
− | |Mark point of intersection as 'C' Let's Move point 'B',& 'C' how the perpendicular bisector and point 'C' move along with point 'B'. | + | |Mark point of intersection as '''C''' Let's Move point '''B''',& '''C''' how the perpendicular bisector and point '''C''' move along with point '''B'''. |
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|02:59 | |02:59 | ||
− | |How to verify 'C' is the midpoint of 'AB'? | + | |How to verify '''C''' is the midpoint of '''AB'''? |
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|03:02 | |03:02 | ||
− | |Click on | + | |Click on '''Distance''' tool. click on the points '''A''' , '''C'''. '''C''' ,'''B''' Notice that '''AC''' = '''CB''' implies 'C' is the midpoint of 'AB'. |
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|03:20 | |03:20 | ||
− | |Select | + | |Select '''Compass''' tool from tool bar,C lick on the points '''C''', '''B'''. and '''C''' once again... to complete the figure. |
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|03:33 | |03:33 | ||
− | |Click on the | + | |Click on the '''Intersect two objects''' tool Mark the points of intersection as '''D''' and '''E''' |
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|03:42 | |03:42 | ||
− | |Select | + | |Select '''Segment between two points''' tool. |
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|03:45 | |03:45 | ||
− | |Join points 'B', 'D' and 'B' , 'E' . | + | |Join points '''B''', '''D''' and '''B''' , '''E''' . |
− | + | ||
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|03:53 | |03:53 | ||
− | |Segments 'BD' and 'BE' are tangents to the circle 'c'? | + | |Segments '''BD''' and '''BE''' are tangents to the circle '''c'''? |
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|04:05 | |04:05 | ||
− | |Select | + | |Select '''Segment between two points''' tool. |
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|04:08 | |04:08 | ||
− | |Join points 'A', 'D' and 'A', 'E'. | + | |Join points '''A''', '''D''' and '''A''', '''E'''. |
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|04:14 | |04:14 | ||
− | |In triangles 'ADB' and 'ABE' Segment 'AD'= segment 'AE' (radii of the circle 'c'). | + | |In triangles '''ADB''' and '''ABE''' Segment '''AD'''= segment '''AE''' (radii of the circle 'c'). |
− | Let's see from the Algebra view that segment 'AD'=segment 'AE'. | + | Let's see from the Algebra view that segment '''AD'''=segment '''AE'''. |
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|04:34 | |04:34 | ||
− | |'∠ADB'= '∠BEA' angle of the semicircle of circle 'D' Lets measure the "Angle". | + | |'''∠ADB'''= '''∠BEA''' angle of the semicircle of circle '''D''' Lets measure the "Angle". |
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|04:48 | |04:48 | ||
− | |Click on the | + | |Click on the '''Angle''' tool... Click on the points '''A''', '''D''', '''B''' and '''B''', '''E''', '''A''' angles are equal. |
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|05:03 | |05:03 | ||
− | |Segment 'AB' is common to both the triangles,therefore '△ADB' '≅' '△ABE' by | + | |Segment '''AB''' is common to both the triangles,therefore '''△ADB''' '≅' '''△ABE''' by '''SAS rule of congruency''' |
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|05:20 | |05:20 | ||
− | |It implies Tangents 'BD' and 'BE' are equal! | + | |It implies Tangents '''BD''' and '''BE''' are equal! |
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|05:26 | |05:26 | ||
− | |From the Algebra view, we can find that tangents 'BD' and 'BE' are equal | + | |From the Algebra view, we can find that tangents '''BD''' and '''BE''' are equal |
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|Please Notice that tangent is always at right angles to the radius of the circle where it touches, | |Please Notice that tangent is always at right angles to the radius of the circle where it touches, | ||
− | Let us move the point 'B' & 'C' how the tangents move along with point 'B'. | + | Let us move the point 'B' & 'C' how the tangents move along with point '''B'''. |
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|05:50 | |05:50 | ||
− | |Let us save the file now. Click on | + | |Let us save the file now. Click on '''File'''>> '''Save As''' |
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|05:54 | |05:54 | ||
− | |I will type the file name as | + | |I will type the file name as '''Tangent-circle''' Click on '''Save''' |
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|06:11 | |06:11 | ||
− | | | + | |'''Angle between tangent and chord at the point of tangency, is same as an inscribed angle subtended by the same chord'''. |
Angle DFB between tangents & chord= inscribed angle FCB of the chord BF. | Angle DFB between tangents & chord= inscribed angle FCB of the chord BF. | ||
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|06:38 | |06:38 | ||
− | |Let's open a new Geogebra window.click on | + | |Let's open a new Geogebra window.click on '''File''' >> '''New'''. Let's draw a circle. |
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|06:48 | |06:48 | ||
− | |Click on the | + | |Click on the '''Circle with center through point''' tool from tool bar . Mark a point '''A''' as a centre and click again to get '''B'''. |
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|06:59 | |06:59 | ||
− | |Select | + | |Select '''New point''' tool.Mark point'''C''' on the circumference and '''D''' outside the circle. |
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|07:06 | |07:06 | ||
− | |Select | + | |Select '''Tangents''' tool from toolbar.click on the point '''D'''... and on circumference. |
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|07:20 | |07:20 | ||
− | |Click on the | + | |Click on the '''Intersect two objects''' tool Mark points of contact as '''E''' and '''F'''. |
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|07:28 | |07:28 | ||
− | |Let's draw a triangle.Click on the | + | |Let's draw a triangle.Click on the '''Polygon''' tool. |
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|07:31 | |07:31 | ||
− | |Click on the points 'B' 'C' 'F' and 'B' once again to complete the figure. | + | |Click on the points '''B''' '''C''' '''F''' and '''B''' once again to complete the figure. |
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|07:41 | |07:41 | ||
− | |In the figure 'BF' is the chord to the circle 'c'. | + | |In the figure '''BF''' is the chord to the circle '''c'''. |
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|07:45 | |07:45 | ||
− | |'∠FCB' is the inscribed angle by the chord to the circle 'c'. | + | |'''∠FCB''' is the inscribed angle by the chord to the circle '''c'''. |
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|07:53 | |07:53 | ||
− | |'∠DFB' is angle between tangent and chord to the circle 'c'. | + | |'''∠DFB''' is angle between tangent and chord to the circle '''c'''. |
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|08:01 | |08:01 | ||
− | |Lets Measure the angles, Click on the | + | |Lets Measure the angles, Click on the '''Angle''' tool, click on the points D' 'F' 'B' and 'F' 'C' 'B'. |
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|08:14 | |08:14 | ||
− | |Notice that '∠DFB' = '∠FCB'. Let us move the point 'D' & 'C' that tangents and chords move along with point 'D'. | + | |Notice that '''∠DFB''' = '''∠FCB'''. Let us move the point '''D''' & '''C''' that tangents and chords move along with point 'D'. |
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|08:31 | |08:31 | ||
− | |Let us save the file now.Click on | + | |Let us save the file now.Click on '''File'''>> '''Save As''' |
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|08:36 | |08:36 | ||
− | |I will type the file name as | + | |I will type the file name as '''Tangent-angle''' Click on "Save" With this we come to the end of this tutorial. |
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|08:57 | |08:57 | ||
− | | | + | |'''Two tangents drawn from an external point are equal''' |
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|09:01 | |09:01 | ||
− | | | + | |'''Angle between a tangent and radius of a circle is 90^0''' |
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|09:07 | |09:07 | ||
− | | | + | |'''Angle between tangent and a chord is equal to inscribed angle subtended by the chord''' |
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|09:17 | |09:17 | ||
− | | | + | |'''Angle between tangents drawn to an circle, is supplementary to the angle subtended by the line-segment joining the points of contact at the centre'''. |
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Revision as of 16:53, 3 September 2014
Time | Narration |
00:00 | Hello Welcome to this tutorial on Tangents to a circle in Geogebra. |
00:06 | At the end of this tutorial you will be able to Draw tangents to the circle,Understand the properties of Tangents. |
00:17 | We assume that you have the basic working knowledge of Geogebra. |
00:22 | If not,For relevant tutorials Please visit our website http://spoken-tutorial.org. |
00:27 | To record this tutorial, I am using Ubuntu Linux OS Version 11.10, Geogebra Version 3.2.47.0 . |
00:41 | We will use the following Geogebra tools
.Tangents, .Perpendicular Bisector, .Intersect two Objects, .Compass, .Polygon & .Circle with Center and Radius. |
00:58 | Let's open a new GeoGebra window. |
01:01 | Click on Dash home Media Applications. Under Type Choose Education and GeoGebra. |
01:13 | let's define tangents to a circle. |
01:16 | Tangent is a line that touches a circle at only one point. |
01:22 | The point of contact is called "point of tangency". |
01:27 | For this tutorial I will use Grid layout instead of "Axes",Right Click on the drawing pad. |
01:35 | uncheck Axes Select Grid |
01:39 | let us draw tangent to a circle. |
01:42 | First let us draw a circle. |
01:45 | Select “Circle with Center and Radius” tool from toolbar. |
01:49 | Mark a point 'A' on the drawing pad. |
01:52 | A dialogue box opens. |
01:53 | Let's type value 3 for radius,Click OK |
01:58 | A circle with centre A and radius 3 cm is drawn. |
02:04 | Let's Move the point A & see that circle has same radius. |
02:09 | Click on the New pointtool,Mark a point 'B' outside the circle. |
02:15 | "Select Segment between two points" tool.Join points A and B.A Segment AB is drawn. |
02:25 | Select Perpendicular Bisector tool, Click on the points A & B.Perpendicular bisector to segment 'AB' is drawn. |
02:37 | Segment AB and Perpendicular bisector intersect at a point,Click on Intersect two objects tool. |
02:44 | Mark point of intersection as C Let's Move point B,& C how the perpendicular bisector and point C move along with point B. |
02:59 | How to verify C is the midpoint of AB? |
03:02 | Click on Distance tool. click on the points A , C. C ,B Notice that AC = CB implies 'C' is the midpoint of 'AB'.
|
03:20 | Select Compass tool from tool bar,C lick on the points C, B. and C once again... to complete the figure. |
03:30 | Two circles intersect at two points.
|
03:33 | Click on the Intersect two objects tool Mark the points of intersection as D and E |
03:42 | Select Segment between two points tool. |
03:45 | Join points B, D and B , E . |
03:53 | Segments BD and BE are tangents to the circle c? |
03:59 | let's explore some of the properties of these Tangents to the circle. |
04:05 | Select Segment between two points tool. |
04:08 | Join points A, D and A, E. |
04:14 | In triangles ADB and ABE Segment AD= segment AE (radii of the circle 'c').
Let's see from the Algebra view that segment AD=segment AE. |
04:34 | ∠ADB= ∠BEA angle of the semicircle of circle D Lets measure the "Angle". |
04:48 | Click on the Angle tool... Click on the points A, D, B and B, E, A angles are equal. |
05:03 | Segment AB is common to both the triangles,therefore △ADB '≅' △ABE by SAS rule of congruency |
05:20 | It implies Tangents BD and BE are equal! |
05:26 | From the Algebra view, we can find that tangents BD and BE are equal |
05:33 | Please Notice that tangent is always at right angles to the radius of the circle where it touches,
Let us move the point 'B' & 'C' how the tangents move along with point B. |
05:50 | Let us save the file now. Click on File>> Save As |
05:54 | I will type the file name as Tangent-circle Click on Save |
06:08 | Let's state a theorem |
06:11 | Angle between tangent and chord at the point of tangency, is same as an inscribed angle subtended by the same chord.
Angle DFB between tangents & chord= inscribed angle FCB of the chord BF. |
06:34 | Let's verify the theorem; |
06:38 | Let's open a new Geogebra window.click on File >> New. Let's draw a circle. |
06:48 | Click on the Circle with center through point tool from tool bar . Mark a point A as a centre and click again to get B. |
06:59 | Select New point tool.Mark pointC on the circumference and D outside the circle. |
07:06 | Select Tangents tool from toolbar.click on the point D... and on circumference. |
07:14 | Two Tangents are drawn to the circle. |
07:16 | Tangents meet at two points on the circle. |
07:20 | Click on the Intersect two objects tool Mark points of contact as E and F. |
07:28 | Let's draw a triangle.Click on the Polygon tool. |
07:31 | Click on the points B C F and B once again to complete the figure. |
07:41 | In the figure BF is the chord to the circle c. |
07:45 | ∠FCB is the inscribed angle by the chord to the circle c. |
07:53 | ∠DFB is angle between tangent and chord to the circle c. |
08:01 | Lets Measure the angles, Click on the Angle tool, click on the points D' 'F' 'B' and 'F' 'C' 'B'. |
08:14 | Notice that ∠DFB = ∠FCB. Let us move the point D & C that tangents and chords move along with point 'D'. |
08:31 | Let us save the file now.Click on File>> Save As |
08:36 | I will type the file name as Tangent-angle Click on "Save" With this we come to the end of this tutorial. |
08:50 | Let's summarize,In this tutorial, we have learnt to verify that; |
08:57 | Two tangents drawn from an external point are equal |
09:01 | Angle between a tangent and radius of a circle is 90^0 |
09:07 | Angle between tangent and a chord is equal to inscribed angle subtended by the chord |
09:14 | As an assignment I would like you to verify: |
09:17 | Angle between tangents drawn to an circle, is supplementary to the angle subtended by the line-segment joining the points of contact at the centre. |
09:30 | To verify ,Draw a circle.
Draw tangents from an external point. |
09:37 | Mark points of contact of the tangents. Join centre of circle to points of contact. |
09:44 | Measure angle at the centre, Measure angle between the tangents. |
09:49 | What is the sum of about two angles? Join centre and external point. |
09:55 | Does the line-segment bisect the angle at the centre? Hint - Use Angle Bisector tool. |
10:05 | The output should look like this,
|
10:08 | Sum of the angles is 180^0. The line segments bisects the angle.
|
10:16 | Watch the video available at this url http://spoken-tutorial.org/ |
10:19 | It summarises the Spoken Tutorial project. If you do not have good bandwidth,you can download and watch it |
10:27 | The Spoken tutorial project team Conducts workshops using spoken tutorials. |
10:32 | Gives certificates to those who pass an online test. |
10:35 | For more details, please write to contact@spoken-tutorial.org. |
10:42 | Spoken Tutorial Project is a part of Talk to a Teacher project. |
10:47 | It is supported by the National Mission on Education through ICT, MHRD, Government of India. |
10:54 | More information on this Mission is available at this link http://spoken-tutorial.org/NMEICT-Intro ] |
10:59 | The script is contributed by Neeta Sawant from SNDT Mumbai. |
11:04 | This is Madhuri Ganpathi from IIT Bombay.
Thank you for joining |
Contributors and Content Editors
Madhurig, Minal, PoojaMoolya, Pratik kamble, Sakinashaikh, Sandhya.np14, Sneha