Difference between revisions of "Scilab/C4/Control-systems/Gujarati"

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(Created page with "{| Border=1 |'''Time''' |'''Narration''' |- | 00:01 |Dear Friends, |- | 00:02 | Welcome to the spoken tutorial on ''' Advanced Control of Continuous Time systems'''. |-...")
 
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|Dear Friends,  
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|નમસ્તે મિત્રો,
  
 
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| 00:02
 
| 00:02
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| Welcome to the spoken tutorial on ''' Advanced Control of Continuous Time systems'''.
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| ''' Advanced Control of Continuous Time systems''' પરના આ સ્પોકન ટ્યુટોરિયલમાં તમારું સ્વાગત છે .  
  
 
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| 00:09
 
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| At the end of this tutorial, you will learn how to:
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| આ ટ્યુટોરીયલના અંતમાં તમે શીખીશું કેવી રીતે:  
  
 
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|00:12
 
|00:12
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|* Define a continuous time system: second and higher order
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|* એક '''continuous time system''' બીજી બાજુએ ઉચ્ચ ઓડરને કેવી રીતે વ્યાખ્યાયિત કરાય છે.
  
 
|-
 
|-
 
|00:17
 
|00:17
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|* Plot response to '''step''' and sine inputs  
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|* '''step''' અને  '''sine inputs'''  પર પ્લોટ રિસ્પોન્સ કેવી રીતે બનાવાય છે.
  
 
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| 00:20
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|* Do a '''Bode plot'''  
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|* '''Bode plot''' કેવી રીતે કરાય.
  
 
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|00:22
 
|00:22
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|* Study '''numer''' and ''' denom Scilab functions'''  
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|* '''numer''' અને  ''' denom Scilab functions''' નું કેવી રીતે અભ્યાસ કરાય છે.
  
 
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| 00:26
 
| 00:26
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|* Plot ''' poles''' and '''zeros''' of a system.  
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|* સીસ્ટમ ના  ''' poles''' અને  '''zeros''' કેવી રીતે  પ્લોટ કરાય છે.
  
 
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|To record this tutorial, I am using
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| આ ટ્યુટોરિયલ રિકોર્ડ કરવા માટે હું ઉપયોગ કરી રહી છું,  
  
 
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|00:33
 
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|'''Ubuntu 12.04''' as the operating system with
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| '''Scilab 5.3.3''' વર્જનના સાથે.
  
 
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|'''Scilab 5.3.3''' version.
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|'''Ubuntu 12.04''' ઓપરેટીંગ સિસ્ટમ
  
 
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| 00:40
 
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| Before practicing this tutorial, a learner should have basic knowledge of '''Scilab''' and '''control systems.'''
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| આ ટ્યુટોરીયલ ના અભ્યાસ પહેલા તમને '''Scilab''' અને  '''control systems.''' નું સમાન્ય જ્ઞાન હોવું જરૂરી છે.
  
 
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| 00:48
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| For '''Scilab,''' please refer to the '''Scilab tutorials''' available on the '''Spoken Tutorial website.'''
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| સાઈલેબ માટે સ્પોકન ટ્યુટોરિયલ વેબ સાઈટ પર ઉપલબ્ધ સંબંધિત ટ્યુટોરિયલ જુઓ.  
  
 
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|00:55
 
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|In this tutorial, I will describe how to define '''second-order linear system.'''  
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| આ ટ્યુટોરિયલ માં હું તમને બતાવીશ કે  '''second-order linear system.''' ને કેવી રીતે વ્યાખ્યાયિત કરાવાય.
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|01:02
 
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| So, first we have to define '''complex domain variable 's'.'''  
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| તો પ્રથમ આપણે '''complex domain variable 's'.''' વ્યાખ્યાયિત કરીશું.
  
 
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|Let us switch to the ''' Scilab console window.'''
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| ચાલો ''' Scilab console window.''' પર પાછા જઈએ.
  
 
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|Here, type '''s equal to poly open parenthesis zero comma open single quote s close single quote close parenthesis''', press '''Enter.'''  
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|અહી ટાઈપ કરો  '''s equal to poly ખુલ્લો  કૌંસ  zero comma ખુલ્લો એકલ અવતરણ  s એકલ અવતરણ ને બંદ કરો  બંદ કૌંસ  ''', '''Enter.''' દબાવો.
  
 
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|The output is''' 's'.'''
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|આઉટપુટ ''' 's'.''' છે.
  
 
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|There is another way to define''' 's' '''as '''continuous time complex variable.'''
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| ''' '''as '''continuous time complex variable.''' ને ''''s'''' ની જેમ વ્યાખ્યાયિત કરવાનો હજી એક માર્ગ છે.
  
 
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|On the '''console''' window, type:  
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| '''console''' વિન્ડો પર ટાઈપ કરો,:  
  
 
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| '''s equal to percentage s''', press '''Enter.'''  
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| '''s equal to percentage s''', '''Enter.''' દબાવો.
  
 
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|01:41
 
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|Let us study the '''syslin Scilab command.'''  
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| ચાલો '''syslin Scilab command.''' નો અભ્યાસ કરીએ.
 
   
 
   
 
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|Use the '''Scilab''' function''' ’syslin’ ''' to define the continuous time system.  
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| '''continuous time system''' ને વ્યાખ્યાયિત કરવા માટે સાઈલેબ ફંક્શન '''syslin''' નો ઉપયોગ કરીએ છીએ.  
  
 
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|Use '''csim''' with '''step''' option, to obtain '''the step response''' and then plot the '''step response'''.  
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|'''step response''' મેળવવા માટે  '''step''' ના સાથે '''csim''' ઉપયોગ કરો અને અને પછી ''' step response''' ને પ્લોટ કરો.  
  
 
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Revision as of 11:35, 4 January 2016

Time Narration
00:01 નમસ્તે મિત્રો,
00:02 Advanced Control of Continuous Time systems પરના આ સ્પોકન ટ્યુટોરિયલમાં તમારું સ્વાગત છે .
00:09 આ ટ્યુટોરીયલના અંતમાં તમે શીખીશું કેવી રીતે:
00:12 * એક continuous time system બીજી બાજુએ ઉચ્ચ ઓડરને કેવી રીતે વ્યાખ્યાયિત કરાય છે.
00:17 * step અને sine inputs પર પ્લોટ રિસ્પોન્સ કેવી રીતે બનાવાય છે.
00:20 * Bode plot કેવી રીતે કરાય.
00:22 * numer અને denom Scilab functions નું કેવી રીતે અભ્યાસ કરાય છે.
00:26 * સીસ્ટમ ના poles અને zeros કેવી રીતે પ્લોટ કરાય છે.
00:30 આ ટ્યુટોરિયલ રિકોર્ડ કરવા માટે હું ઉપયોગ કરી રહી છું,
00:33 Scilab 5.3.3 વર્જનના સાથે.
00:36 Ubuntu 12.04 ઓપરેટીંગ સિસ્ટમ
00:40 આ ટ્યુટોરીયલ ના અભ્યાસ પહેલા તમને Scilab અને control systems. નું સમાન્ય જ્ઞાન હોવું જરૂરી છે.
00:48 સાઈલેબ માટે સ્પોકન ટ્યુટોરિયલ વેબ સાઈટ પર ઉપલબ્ધ સંબંધિત ટ્યુટોરિયલ જુઓ.
00:55 આ ટ્યુટોરિયલ માં હું તમને બતાવીશ કે second-order linear system. ને કેવી રીતે વ્યાખ્યાયિત કરાવાય.
01:02 તો પ્રથમ આપણે complex domain variable 's'. વ્યાખ્યાયિત કરીશું.
01:08 ચાલો Scilab console window. પર પાછા જઈએ.
01:11 અહી ટાઈપ કરો s equal to poly ખુલ્લો કૌંસ zero comma ખુલ્લો એકલ અવતરણ s એકલ અવતરણ ને બંદ કરો બંદ કૌંસ , Enter. દબાવો.
01:25 આઉટપુટ 's'. છે.
01:27 as continuous time complex variable. ને 's' ની જેમ વ્યાખ્યાયિત કરવાનો હજી એક માર્ગ છે.
01:32 console વિન્ડો પર ટાઈપ કરો,:
01:35 s equal to percentage s, Enter. દબાવો.
01:41 ચાલો syslin Scilab command. નો અભ્યાસ કરીએ.
01:44 continuous time system ને વ્યાખ્યાયિત કરવા માટે સાઈલેબ ફંક્શન syslin નો ઉપયોગ કરીએ છીએ.
01:51 G of s is equal to 2 over 9 plus 2 s plus s square.
01:58 step response મેળવવા માટે step ના સાથે csim ઉપયોગ કરો અને અને પછી step response ને પ્લોટ કરો.
02:06 Let us switch to the Scilab console window.
02:09 Here, type: sys capital G equal to syslin open parenthesis open single quote c close single quote comma two divide by open parenthesis s square plus two asterisk s plus nine close parenthesis close parenthesis
02:32 Here c is used, as we are defining a continuous time system.
02:38 Press Enter.
02:40 The output is linear second order system represented by
02:44 2 over 9 plus 2 s plus s square.
02:49 Then, type t equal to zero colon zero point one colon ten semicolon
02:57 Press Enter.
02:59 Then type y one is equal to c sim open parenthesis open single quote step close single quote comma t comma sys capital G close the parenthesis semicolon
03:15 Press Enter.
03:17 Then type plot open parenthesis t comma y one close parenthesis semicolon
03:24 Press Enter.
03:26 The output will display the step response of the given second order system.
03:33 Let us study the Second Order system response for sine input.
03:39 Sine inputs can easily be given as inputs to a second order system to a continuous time system.
03:47 Let us switch to the Scilab console window.
03:51 Type U two is equal to sine open parenthesis t close parenthesis semicolon.
03:59 Press Enter.
04:01 Then type: y two is equal to c sim open parenthesis u two comma t comma sys capital G close the bracket semicolon.
04:15 Press Enter.
04:17 Here we are using sysG, the continuous time second order system, we had defined earlier.
04:25 Then type: plot open parenthesis t comma open square bracket u two semicolon y two close square bracket close parenthesis.
04:39 Make sure that you place a semicolon between u2 and y2 because u2 and y2 are row vectors of the same size.
04:50 Press Enter.
04:52 This plot shows the response of the system to a step input and sine input. It is called the response plot.
05:01 Response Plot plots both the input and the output on the same graph.
05:06 As expected, the output is also a sine wave and
05:11 there is a phase lag between the input and output.
05:15 Amplitude is different for the input and the output as it is being passed through a transfer function.
05:23 This is a typical under-damped example.
05:26 Let us plot bode plot of 2 over 9 plus 2 s plus s square.
05:32 Please note, command 'f r e q' is a Scilab command for frequency response.
05:39 Do not use f r e q as a variable!!
05:44 Open the Scilab console and type:
05:47 f r is equal to open square bracket zero point zero one colon zero point one colon ten close square bracket semicolon.
06:00 Press Enter.
06:03 The frequency is in Hertz.
06:06 Then type bode open parenthesis sys capital G comma fr close parenthesis.
06:15 and press Enter.
06:17 The bode plot is shown.
06:20 Let us define another system.
06:23 We have an over-damped system p equal to s square plus nine s plus nine
06:32 Let us plot step response for this system.
06:36 Switch to Scilab console.
06:38 Type this on your console:
06:40 p is equal to s square plus nine asterisk s plus nine
06:47 and then press Enter.
06:49 Then type this on your console:
06:51 sys two is equal to syslin open parenthesis open single quote c close single quote comma nine divided by p close parenthesis
07:04 and press Enter.
07:07 Then type: t equal to zero colon zero point one colon ten semicolon
07:14 Press Enter.
07:17 y is equal to c sim open parenthesis open single quote step close single quote comma t comma sys two close parenthesis semicolon.
07:31 Press Enter.
07:33 Then type plot open parenthesis t comma y close parenthesis.
07:39 Press Enter.
07:41 The response plot for over damped system is shown.
07:46 To find the roots of p type this on your console -
07:49 roots of p and press Enter.
07:54 These roots are the poles of the system sys two.
07:59 The roots or poles of the system are shown.
08:02 Please plot Step response for this system along similar lines, as for over damped system.
08:11 G of s is equal to 2 over 9 plus 6 s plus s square which is a critically damped system
08:20 Then G of s is equal to two over 9 plus s square which is an undamped system
08:28 G of s is equal to 2 over 9 minus 6 s plus s square which is an unstable system
08:36 Check response to sinusoidal inputs for all the cases and plot bode plot too.
08:45 Switch to Scilab console.
08:48 For a general transfer function, the numerator and denominator can be specified separately.
08:55 Let me show you how.
08:57 Type on console:
08:59 sys three is equal to syslin open parenthesis open single quote c close single quote comma s plus six comma s square plus six asterisk s plus nineteen close parenthesis.
09:19 Press Enter.
09:21 Another way of defining a system is to type:
09:24 g is equal to open parenthesis s plus six close parenthesis divided by open parenthesis s square plus six asterisk s plus nineteen close parenthesis
09:40 Press Enter.
09:42 Then type this on your console:
09:44 sys four is equal to syslin open parenthesis open single quote c close single quote comma g close parenthesis.
09:55 Press Enter.
09:58 Both ways, we get the same output;
10:01 six plus s over 19 plus six s plus s square.
10:07 The variable ’sys’ is of type ’rational’.
10:10 Its numerator and denominator can be extracted by various ways.
10:16 Sys of two, numer of sys or numer of g gives the numerator.
10:22 The denominator can be calculated using sys(3) or denom of sys functions.
10:30 The poles and zeros of the system can be plotted using p l z r function.
10:37 The syntax is p l z r of sys.
10:41 The plot shows 'x for poles' and 'circles for zeros'.
10:46 Switch to Scilab console.
10:48 Type this on your Scilab console:
10:50 sys three open parenthesis two close parenthesis.
10:55 Press Enter.
10:56 This gives the numerator of the rational function sys three that is '6 + s'.
11:03 Otherwise, you can type:
11:05 numer open parenthesis sys three close parenthesis.
11:11 Press Enter.
11:13 The numerator of system three is shown.
11:17 To get the denominator, type:
11:19 sys three open parenthesis three close parenthesis. Press Enter.
11:26 The denominator of the function is shown.
11:30 You can also type denom open parenthesis sys three close parenthesis.
11:36 Press Enter.
11:38 Then type p l z r open parenthesis sys three close parenthesis.
11:44 Press Enter.
11:47 The output graph plots the poles and zeros.
11:50 It shows 'cross and circle' for 'poles and zeros' of the system respectively.
11:58 It is plotted on the complex plane.
12:01 In this tutorial, we have learnt how to:
12:03 * Define a system by its transfer function.
12:08 * Plot step and sinusoidal responses.
12:11 * Extract poles and zeros of a transfer function.
12:15 Watch the video available at the following link.
12:19 It summarizes the Spoken Tutorial project.
12:22 If you do not have good bandwidth, you can download and watch it.
12:27 The spoken tutorial project Team:
12:29 Conducts workshops using spoken tutorials.
12:32 Gives certificates to those who pass an online test.
12:36 For more details, please write to contact@spoken-tutorial.org.
12:43 Spoken Tutorial Project is a part of the Talk to a Teacher project.
12:47 It is supported by the National Mission on Eduction through ICT, MHRD, Government of India.
12:55 More information on this mission is available at spoken-tutorial.org/NMEICT-Intro.
13:06 This is Ashwini Patil, signing off.
13:08 Thank you for joining. Good Bye.

Contributors and Content Editors

Jyotisolanki

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