# Scilab/C4/Solving-Non-linear-Equations/English

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Title of script: Solving Nonlinear Equations using Numerical Methods

Author: Shamika

Keywords: Nonlinear equation, root, zero

Visual Cue

Narration
Slide 1 Dear Friends,

Welcome to the spoken tutorial on “Solving Nonlinear Equations using Numerical Methods

Slide 2,3 -Objectives At the end of this tutorial, you will learn how to:
• Solve nonlinear equations using numerical methods
• The methods we will be studying are
• Bisection method
• and Secant method
• We will also develop Scilab code to solve nonlinear equations

Slide 4-System Requirements To record this tutorial, I am using
• Ubuntu 12.04 as the operating system
• and Scilab 5.3.3 version

Slide 5- Prerequisites Before practising this tutorial, a learner should have
• basic knowledge of Scilab and
• nonlinear equations

For Scilab, please refer to the Scilab tutorials available on the Spoken Tutorial website.

Slide 6 For a given function f , we have to find the value of x for which f of x is equal to zero.

This solution x is called root of equation or zero of function f

This process is called root finding or zero finding

Slide 7 We begin by studying Bisection Method.

• In bisection method, we calculate the initial bracket of the root.
• Then we iterate through the bracket and halve its length.
• We repeat this proces until we find the solution of the equation.

Slide 8 Let us solve this function using Bisection method

Given

function f equal to two sin x minus e to the power of x divided by four minus one in the interval minus five and minus three.

Open Bisection.sci on Scilab Editor * Open Bisection dot sci on Scilab editor
• Let us look at the code for Bisection method
• We define the function Bisection with input arguments a b f and tol
• Here a is the lower limit of the interval
• b is the upper limit of the interval
• f is the function to be solved
• and tol is th etolerance level
• We specify the maximum number of iterations to be equal to hundred.
• We find the midpoint of the interval and iterate till the value calculated is within the specified tolerance range.

Click on Execute and select Save and Execute Let us solve the problem using this code.

Save and execute the file

Switch to Scilab console

On Scilab Console type,

a=-5

Press enter

b=-3

Press enter

deff('[y]=f(x)','y=(2*(sin(x))-((%e^x)/4)-1')

Press enter

Tol=10^-5

Press enter

Bisection(a,b,f,Tol)

Press enter

Switch to Scilab console

Let us define the interval.

Let a be equal to minus five

Press enter

Let b be equal to minus three.

Press enter

Define the function using deff function.

We type

deff open paranthesis open single quote open square bracket y close square bracket equal to f of x close single quote comma open single quote y equal to two asterisk sin of x minus open paranthesis open paranthesis percentage e to the power of x close paranthesis divided by four close paranthesis minus one close single quote close paranthesis

To know more about deff function, type help deff

Press enter

Let tol be equal to 10 to the power of minus five

Press enter

To solve the problem, type

Bisection open paranthesis a comma b comma f comma tol close paranthesis

Press enter

The root of the function is shown on the console

Slide 12 Let us study Secant's method.

In Secan't method, the derivative is approximated by finite

difference using two successive Pls use a simpler word. This word

will pose a problem for our translators.Reply to nancy (12/23/2013, 11:33): "..."

Changed. iteration values.

Slide 13 Let us solve this example using Secant method

The function is f equal to x square minus six.

The two starting guesses are , p zero equal to two and p one equal to three.

Open Secant.sci on Scilab Editor Before we solve the problem, let us look at the code for Secant meethod.

Open Secant dot sci on Scilab editor

We define the function secant with input arguments a, b and f

a is first starting guess for the root

b is the second starting guess and f is the function to be solved.

We find the difference between the value at the current point and the previous point.

We apply Secant's method and find the value of the root.

Finally we end the function

Click on Execute and select Save and Execute Let me save and execute the code.
Switch to Scilab console

Type on Scilab console

clc

Press enter

a=2

Press enter

b=3

Press enter

deff('[y]=g(x)','y=(x^2)-6')

Press enter

Secant(a,b,g)

Press enter

Switch to Scilab console

Type clc

Press enter

Let me define the initial guesses for this example. Type

a equal to 2

Press enter

Then type

b equal to 3

Press enter

We define the function using deff function.

Type

deff open paranthesis open single quote open square bracket y close square bracket equal to g of x close single quote comma open single quote y equal to open paranthesis x to the power of two close paranthesis minus six close single quote close paranthesis

Press enter

We call the function by typing

Secant open paranthesis a comma b comma g close paranthesis.

Press enter

The value of the root is shown on the console

Slide 14 Let us summarize this tutorial

In this tutorial we have learnt to:

• Find the roots of nonlinear equation
• Develop Scilab code for different solving methods

Slide 15- Assignment Solve this problem on your own using the two methods we learnt today.
Show Slide 16

Title: About the Spoken Tutorial Project

• It summarises the Spoken Tutorial project
• If you do not have good bandwidth, you can download and watch it

* Watch the video available at the following link
• It summarises the Spoken Tutorial project
• If you do not have good bandwidth, you can download and watch it

Show Slide 17

Title: Spoken Tutorial Workshops

The Spoken Tutorial Project Team

• Conducts workshops using spoken tutorials
• Gives certificates for those who pass an online test
• For more details, please write to contact@spoken-tutorial.org

The Spoken Tutorial Project Team
• Conducts workshops using spoken tutorials
• Gives certificates for those who pass an online test
• For more details, please write to contact at spoken hyphen tutorial dot org

Show Slide 18

Title: Acknowledgement

• Spoken Tutorial Project is a part of the Talk to a Teacher project
• It is supported by the National Mission on Education through ICT, MHRD, Government of India