Scilab/C4/Control-systems/Gujarati - Revision history

Jyotisolanki at 12:01, 27 March 2017

2017-03-27T12:01:29Z

Jyotisolanki at 09:56, 1 February 2016

2016-02-01T09:56:07Z

Jyotisolanki at 09:51, 4 January 2016

2016-01-04T09:51:20Z

Jyotisolanki at 09:50, 4 January 2016

2016-01-04T09:50:10Z

Show changes

Jyotisolanki at 07:11, 4 January 2016

2016-01-04T07:11:22Z

Show changes

Jyotisolanki at 06:05, 4 January 2016

2016-01-04T06:05:14Z

Jyotisolanki: Created page with "{| Border=1 |'''Time''' |'''Narration''' |- | 00:01 |Dear Friends, |- | 00:02 | Welcome to the spoken tutorial on ''' Advanced Control of Continuous Time systems'''. |-..."

2016-01-04T05:22:19Z

Created page with "{| Border=1 |'''Time''' |'''Narration''' |- | 00:01 |Dear Friends, |- | 00:02 | Welcome to the spoken tutorial on ''' Advanced Control of Continuous Time systems'''. |-..."

New page

{| Border=1

|'''Time'''

|'''Narration'''

|-
| 00:01
|Dear Friends,

|-
| 00:02
| Welcome to the spoken tutorial on ''' Advanced Control of Continuous Time systems'''.

|-
| 00:09
| At the end of this tutorial, you will learn how to:

|-
|00:12
|* Define a continuous time system: second and higher order

|-
|00:17
|* Plot response to '''step''' and sine inputs

|-
| 00:20
|* Do a '''Bode plot'''

|-
|00:22
|* Study '''numer''' and ''' denom Scilab functions'''

|-
| 00:26
|* Plot ''' poles''' and '''zeros''' of a system.

|-
| 00:30
|To record this tutorial, I am using

|-
|00:33
|'''Ubuntu 12.04''' as the operating system with

|-
|00:36
|'''Scilab 5.3.3''' version.

|-
| 00:40
| Before practicing this tutorial, a learner should have basic knowledge of '''Scilab''' and '''control systems.'''

|-
| 00:48
| For '''Scilab,''' please refer to the '''Scilab tutorials''' available on the '''Spoken Tutorial website.'''

|-
|00:55
|In this tutorial, I will describe how to define '''second-order linear system.'''

|-
|01:02
| So, first we have to define '''complex domain variable 's'.'''

|-

|01:08

|Let us switch to the ''' Scilab console window.'''

|-

|01:11
|Here, type '''s equal to poly open parenthesis zero comma open single quote s close single quote close parenthesis''', press '''Enter.'''

|-

| 01:25

|The output is''' 's'.'''

|-

| 01:27
|There is another way to define''' 's' '''as '''continuous time complex variable.'''

|-

|01:32

|On the '''console''' window, type:

|-

|01:35

| '''s equal to percentage s''', press '''Enter.'''

|-
|01:41
|Let us study the '''syslin Scilab command.'''

|-

|01:44

|Use the '''Scilab''' function''' ’syslin’ ''' to define the continuous time system.

|-

|01:51

||''' G of s is equal to 2 over 9 plus 2 s plus s square'''.

|-
|01:58
|Use '''csim''' with '''step''' option, to obtain '''the step response''' and then plot the '''step response'''.

|-

| 02:06
|Let us switch to the '''Scilab console''' window.

|-

|02:09

||Here, type: '''sys''' capital '''G''' '''equal to syslin open parenthesis open single quote c close single quote comma two divide by open parenthesis s square plus two asterisk s plus nine close parenthesis close parenthesis'''

|-

|02:32

| Here '''c''' is used, as we are defining a continuous time system.

|-

|02:38

| Press '''Enter'''.

|-

| 02:40

||The output is linear second order system represented by

|-
| 02:44
|'''2 over 9 plus 2 s plus s square'''.

|-
|02:49
| Then, type '''t equal to zero colon zero point one colon ten semicolon'''

|-
|02:57
| Press '''Enter.'''

|-
| 02:59
|Then type ''' y one is equal to c sim open parenthesis open single quote step close single quote comma t comma sys capital G close the parenthesis semicolon'''

|-
| 03:15
|Press '''Enter.'''

|-
| 03:17
|Then type ''' plot open parenthesis t comma y one close parenthesis semicolon'''

|-
| 03:24
|Press '''Enter.'''

|-
|03:26
|The output will display the '''step response''' of the given second order system.

|-
|03:33
|Let us study the '''Second Order system response''' for '''sine input.'''

|-

| 03:39

|'''Sine inputs''' can easily be given as inputs to a '''second order system to a continuous time system.'''

|-

| 03:47
|Let us switch to the '''Scilab console''' window.

|-

|03:51

|| Type '''U two is equal to sine open parenthesis t close parenthesis semicolon'''.

|-

| 03:59
| Press '''Enter.'''

|-

| 04:01

|Then type: '''y two is equal to c sim open parenthesis u two comma t comma sys capital G close the bracket semicolon'''.

|-

| 04:15

| Press '''Enter'''.

|-

|04:17

||Here we are using ''' sysG, the continuous time second order system''', we had defined earlier.

|-

|04:25

|Then type: '''plot open parenthesis t comma open square bracket u two semicolon y two close square bracket close parenthesis'''.

|-

| 04:39

|Make sure that you place a '''semicolon''' between '''u2''' and '''y2''' because '''u2''' and '''y2''' are row vectors of the same size.

|-

| 04:50

|Press '''Enter.'''

|-

| 04:52

| This plot shows the '''response of the system''' to a '''step input''' and '''sine input. '''It is called the '''response plot. '''

|-

| 05:01

|'''Response Plot''' plots both the input and the output on the same graph.

|-

| 05:06

|As expected, the output is also a '''sine wave''' and

|-

| 05:11

|there is a '''phase lag''' between the input and output.

|-

| 05:15

|'''Amplitude''' is different for the input and the output as it is being passed through a '''transfer''' function.

|-

| 05:23

|This is a typical '''under-damped''' example.

|-

|05:26

|Let us plot ''' bode plot of 2 over 9 plus 2 s plus s square'''.

|-

| 05:32

|Please note, command ''''f r e q'''' is a '''Scilab''' command for '''frequency response.'''

|-

| 05:39

| Do not use '''f r e q''' as a '''variable'''!!

|-

| 05:44

|Open the ''' Scilab console''' and type:
|-

| 05:47

|''' f r is equal to open square bracket zero point zero one colon zero point one colon ten close square bracket semicolon.'''

|-
| 06:00
| Press '''Enter.'''

|-
| 06:03
|The '''frequency''' is in '''Hertz.'''

|-

| 06:06

|Then type '''bode open parenthesis sys capital G comma fr close parenthesis'''.

|-

| 06:15

| and press '''Enter.'''

|-

| 06:17

| The '''bode plot''' is shown.

|-

| 06:20

| Let us define another system.

|-

| 06:23

|We have an ''' over-damped system p equal to s square plus nine s plus nine'''

|-

| 06:32

| Let us plot '''step response''' for this system.

|-

| 06:36

|Switch to '''Scilab console. '''

|-

| 06:38

|Type this on your ''' console''':

|-

| 06:40

|''' p is equal to s square plus nine asterisk s plus nine'''

|-

| 06:47

|and then press ''' Enter.'''

|-

| 06:49

|Then type this on your '''console''':

|-

| 06:51

|'''sys two is equal to syslin open parenthesis open single quote c close single quote comma nine divided by p close parenthesis'''

|-

| 07:04

|and press ''' Enter.'''

|-

| 07:07

|Then type: '''t equal to zero colon zero point one colon ten semicolon '''

|-

| 07:14

|Press '''Enter.'''

|-

| 07:17

|''' y is equal to c sim open parenthesis open single quote step close single quote comma t comma sys two close parenthesis semicolon'''.

|-

| 07:31

|Press '''Enter'''.

|-

| 07:33

|Then type '''plot open parenthesis t comma y close parenthesis'''.

|-

| 07:39

|Press '''Enter.'''

|-

| 07:41

|The '''response plot for over damped system is shown.'''

|-

| 07:46

|To find the '''roots of p''' type this on your '''console - '''

|-

| 07:49

|'''roots of p''' and press '''Enter.'''

|-

| 07:54

|These '''roots''' are the poles of the system '''sys two'''.

|-

| 07:59

|The '''roots or poles''' of the system are shown.

|-

| 08:02

|Please plot '''Step response''' for this system along similar lines, as for '''over damped system.'''

|-

| 08:11

|'''G of s is equal to 2 over 9 plus 6 s plus s square''' which is a '''critically damped system'''

|-

| 08:20

|Then '''G of s is equal to two over 9 plus s square''' which is an '''undamped system'''

|-

| 08:28

|'''G of s is equal to 2 over 9 minus 6 s plus s square''' which is an '''unstable system'''

|-

| 08:36

|Check '''response to sinusoidal inputs''' for all the cases and '''plot bode plot''' too.

|-

| 08:45

|Switch to ''' Scilab console.'''

|-

| 08:48

|For a general '''transfer function''', the numerator and denominator can be specified separately.

|-

| 08:55

| Let me show you how.

|-

| 08:57

|Type on '''console''':

|-

| 08:59

|''' sys three is equal to syslin open parenthesis open single quote c close single quote comma s plus six comma s square plus six asterisk s plus nineteen close parenthesis'''.

|-

| 09:19

|Press '''Enter'''.

|-

| 09:21

|Another way of defining a system is to type:

|-

| 09:24

|'''g is equal to open parenthesis s plus six close parenthesis divided by open parenthesis s square plus six asterisk s plus nineteen close parenthesis'''

|-

| 09:40

|Press '''Enter.'''

|-

| 09:42

|Then type this on your '''console''':

|-

| 09:44

|'''sys four is equal to syslin open parenthesis open single quote c close single quote comma g close parenthesis'''.

|-

| 09:55

|Press '''Enter.'''

|-

| 09:58

|Both ways, we get the same output;

|-

| 10:01

|'''six plus s over 19 plus six s plus s square'''.

|-

| 10:07

|The variable '''’sys’ is of type ’rational’.'''

|-

| 10:10

|Its numerator and denominator can be extracted by various ways.

|-

| 10:16

|'''Sys of two, numer of sys or numer of g''' gives the numerator.

|-

| 10:22

|The denominator can be calculated using '''sys(3) or denom of sys functions.'''

|-

| 10:30

|The '''poles''' and '''zeros''' of the system can be plotted using '''p l z r''' function.

|-

| 10:37

|The syntax is '''p l z r of sys'''.

|-

| 10:41

|The '''plot''' shows 'x for poles' and 'circles for zeros'.

|-

| 10:46

|Switch to Scilab console.

|-

| 10:48

|Type this on your Scilab console:

|-

| 10:50

|'''sys three open parenthesis two close parenthesis'''.

|-

| 10:55

|Press Enter.

|-

| 10:56

|This gives the numerator of the rational function '''sys three''' that is '6 + s'.

|-

| 11:03

|Otherwise, you can type:

|-

| 11:05

|'''numer open parenthesis sys three close parenthesis'''.

|-

| 11:11

|Press Enter.

|-

| 11:13

|The numerator of '''system three''' is shown.

|-

| 11:17

|To get the denominator, type:

|-

| 11:19

|'''sys three open parenthesis three close parenthesis'''. Press Enter.

|-

| 11:26

|The denominator of the function is shown.

|-

| 11:30

|You can also type '''denom open parenthesis sys three close parenthesis'''.

|-

| 11:36

|Press Enter.

|-

| 11:38

|Then type '''p l z r open parenthesis sys three close parenthesis'''.

|-

| 11:44

|Press Enter.

|-

| 11:47

|The output graph plots the '''poles''' and '''zeros'''.

|-

| 11:50

|It shows 'cross and circle' for 'poles and zeros' of the system respectively.

|-

| 11:58

|It is plotted on the complex plane.

|-

| 12:01

|In this tutorial, we have learnt how to:

|-

| 12:03

|* Define a system by its transfer function.

|-

| 12:08

|* Plot step and sinusoidal responses.

|-

| 12:11

|* Extract poles and zeros of a transfer function.

|-
|12:15
| Watch the video available at the following link.

|-

| 12:19

| It summarizes the Spoken Tutorial project.

|-

|12:22

||If you do not have good bandwidth, you can download and watch it.

|-

|12:27

||The spoken tutorial project Team:

|-

|12:29

||Conducts workshops using spoken tutorials.

|-

|12:32

||Gives certificates to those who pass an online test.

|-

|12:36

||For more details, please write to contact@spoken-tutorial.org.

|-

|12:43

|Spoken Tutorial Project is a part of the Talk to a Teacher project.

|-

| 12:47

| It is supported by the National Mission on Eduction through ICT, MHRD, Government of India.
|-

| 12:55

|More information on this mission is available at spoken-tutorial.org/NMEICT-Intro.

|-

| 13:06

|This is Ashwini Patil, signing off.

|-

|13:08

| Thank you for joining. Good Bye.

@@ Line 84: / Line 84: @@
 | 01:27
-| '''  '''as '''continuous time complex variable.''' ને ''''s'''' ની જેમ વ્યાખ્યાયિત કરવાનો હજી એક માર્ગ છે.
+|  '''continuous time complex variable.''' ને ''''s'''' ની જેમ વ્યાખ્યાયિત કરવાનો હજી એક માર્ગ છે.
 |-
@@ Line 96: / Line 96: @@
 |01:35
-| '''s equal to percentage s''',  '''Enter.'''  દબાવો.
+| '''s equal to percentage s'''  '''Enter.'''  દબાવો.
 |-
@@ Line 318: / Line 318: @@
 | 06:06
-|પછી ટાઈપ કરપ  '''bode ખુલ્લો કૌંસ  sys capital G comma fr બંદ કૌંસ'''.
+|પછી ટાઈપ કરો  '''bode ખુલ્લો કૌંસ  sys capital G comma fr બંદ કૌંસ'''.
 |-
@@ Line 330: / Line 330: @@
 | 06:17
-| The '''bode plot''' દેખાય છે.
+| '''bode plot''' દેખાય છે.
 |-
@@ Line 540: / Line 540: @@
 | 09:40
-|Press '''Enter.''' દબાવો.
+| '''Enter.''' દબાવો.
 |-
@@ Line 703: / Line 703: @@
 | 11:38
-|પછી ટાઈપ કરો  '''p l z r open parenthesis sys three close parenthesis'''.
+|પછી ટાઈપ કરો  '''p l z r ખુલ્લો કૌં sys three બંદ કૌંસ'''.
 |-

@@ Line 498: / Line 498: @@
 | 08:48
+|સમાન્ય ટ્રાન્સફર ફંક્શન માટે '''numerator અને  denominator''' ને અલગથી ઉલ્લેખિત કરી શકાય છે.
- સમાન્ય ટ્રાન્સફર ફંક્શન માટે '''numerator અને  denominator''' ને અલગથી ઉલ્લેખિત કરી શકાય છે.
 |-

@@ Line 19: / Line 19: @@
 |-
 |00:12
-|*  એક '''continuous time system''' બીજી બાજુએ ઉચ્ચ ઓડરને કેવી રીતે વ્યાખ્યાયિત કરાય છે.
+|  એક '''continuous time system''' બીજી બાજુએ ઉચ્ચ ઓડરને કેવી રીતે વ્યાખ્યાયિત કરાય છે.
 |-
 |00:17
-|*  '''step''' અને  '''sine inputs'''  પર પ્લોટ રિસ્પોન્સ કેવી રીતે બનાવાય છે.
+|  '''step''' અને  '''sine inputs'''  પર પ્લોટ રિસ્પોન્સ કેવી રીતે બનાવાય છે.
 |-
 | 00:20
-|*  '''Bode plot'''  કેવી રીતે કરાય.
+|  '''Bode plot'''  કેવી રીતે કરાય.
 |-
 |00:22
-|*  '''numer'''  અને  ''' denom Scilab functions''' નું કેવી રીતે અભ્યાસ કરાય છે.
+|  '''numer'''  અને  ''' denom Scilab functions''' નું કેવી રીતે અભ્યાસ કરાય છે.
 |-
 | 00:26
-|* સીસ્ટમ ના  ''' poles''' અને  '''zeros''' કેવી રીતે  પ્લોટ કરાય છે.
+| સીસ્ટમ ના  ''' poles''' અને  '''zeros''' કેવી રીતે  પ્લોટ કરાય છે.
 |-
@@ Line 739: / Line 739: @@
 | 12:03
-|*  આના ટ્રાન્સફર ફંક્શન ના સીસ્ટમને કેવી રીતે વ્યાખ્યાયિત કરાવાય છે.
+|  આના ટ્રાન્સફર ફંક્શન ના સીસ્ટમને કેવી રીતે વ્યાખ્યાયિત કરાવાય છે.
 |-
@@ Line 745: / Line 745: @@
 | 12:08
-|*  '''step અને  sinusoidal''' રિસ્પોન્સ પ્લોટ કરે છે.
+|  '''step અને  sinusoidal''' રિસ્પોન્સ પ્લોટ કરે છે.
 |-
@@ Line 751: / Line 751: @@
 | 12:11
-|* ટ્રાન્સફર ફંક્શન ના '''poles અને  zeros'''  ને  '''Extract'''  કેવી રીતે કરાય છે.
+| ટ્રાન્સફર ફંક્શન ના '''poles અને  zeros'''  ને  '''Extract'''  કેવી રીતે કરાય છે.
 |-

@@ Line 7: / Line 7: @@
 |-
 | 00:01
-|Dear Friends,
+|નમસ્તે મિત્રો,
 |-
 | 00:02
-| Welcome to the spoken tutorial on ''' Advanced Control of Continuous Time systems'''.
+|  ''' Advanced Control of Continuous Time systems''' પરના આ સ્પોકન ટ્યુટોરિયલમાં તમારું સ્વાગત છે .
 |-
 | 00:09
-| At the end of this tutorial, you will learn how to:
+| આ ટ્યુટોરીયલના અંતમાં તમે શીખીશું કેવી રીતે:
 |-
 |00:12
-|* Define a continuous time system: second and higher order
+|*  એક '''continuous time system''' બીજી બાજુએ ઉચ્ચ ઓડરને કેવી રીતે વ્યાખ્યાયિત કરાય છે.
 |-
 |00:17
-|* Plot response to '''step''' and sine inputs
+|*  '''step''' અને  '''sine inputs'''  પર પ્લોટ રિસ્પોન્સ કેવી રીતે બનાવાય છે.
 |-
 | 00:20
-|* Do a '''Bode plot'''
+|*  '''Bode plot'''  કેવી રીતે કરાય.
 |-
 |00:22
-|* Study '''numer''' and ''' denom Scilab functions'''
+|*  '''numer'''  અને  ''' denom Scilab functions''' નું કેવી રીતે અભ્યાસ કરાય છે.
 |-
 | 00:26
-|* Plot ''' poles''' and '''zeros''' of a system.
+|* સીસ્ટમ ના  ''' poles''' અને  '''zeros''' કેવી રીતે  પ્લોટ કરાય છે.
 |-
 | 00:30
-|To record this tutorial, I am using
+| આ ટ્યુટોરિયલ રિકોર્ડ કરવા માટે હું ઉપયોગ કરી રહી છું,
 |-
 |00:33
-|'''Ubuntu 12.04''' as the operating system with
+|  '''Scilab 5.3.3'''  વર્જનના સાથે.
 |-
 |00:36
-|'''Scilab 5.3.3''' version.
+|'''Ubuntu 12.04''' ઓપરેટીંગ સિસ્ટમ
 |-
 | 00:40
-| Before practicing this tutorial, a learner should have basic knowledge of '''Scilab''' and '''control systems.'''
+| આ ટ્યુટોરીયલ ના અભ્યાસ પહેલા તમને '''Scilab''' અને  '''control systems.''' નું સમાન્ય જ્ઞાન હોવું જરૂરી છે.
 |-
 | 00:48
-| For '''Scilab,''' please refer to the '''Scilab tutorials''' available on the '''Spoken Tutorial website.'''
+| સાઈલેબ માટે સ્પોકન ટ્યુટોરિયલ વેબ સાઈટ પર ઉપલબ્ધ સંબંધિત ટ્યુટોરિયલ જુઓ.
 |-
 |00:55
-|In this tutorial, I will describe how to define '''second-order linear system.'''
+| આ ટ્યુટોરિયલ માં હું તમને બતાવીશ કે  '''second-order linear system.'''  ને કેવી રીતે વ્યાખ્યાયિત કરાવાય.
-−
 |-
 |01:02
-| So, first we have to define '''complex domain variable 's'.'''
+|  તો પ્રથમ આપણે '''complex domain variable 's'.'''  વ્યાખ્યાયિત કરીશું.
 |-
@@ Line 69: / Line 68: @@
 |01:08
-|Let us switch to the ''' Scilab console window.'''
+|  ચાલો ''' Scilab console window.''' પર પાછા જઈએ.
 |-
 |01:11
-|Here, type '''s equal to poly open parenthesis zero comma open single quote s close single quote close parenthesis''', press '''Enter.'''
+|અહી ટાઈપ કરો  '''s equal to poly ખુલ્લો  કૌંસ  zero comma ખુલ્લો એકલ અવતરણ  s એકલ અવતરણ ને બંદ કરો  બંદ કૌંસ  ''',  '''Enter.'''  દબાવો.
 |-
@@ Line 80: / Line 79: @@
 | 01:25
-|The output is''' 's'.'''
+|આઉટપુટ ''' 's'.''' છે.
 |-
 | 01:27
-|There is another way to define''' 's' '''as '''continuous time complex variable.'''
+| '''  '''as '''continuous time complex variable.''' ને ''''s'''' ની જેમ વ્યાખ્યાયિત કરવાનો હજી એક માર્ગ છે.
 |-
@@ Line 91: / Line 90: @@
 |01:32
-|On the '''console''' window, type:
+| '''console''' વિન્ડો પર ટાઈપ કરો,:
 |-
@@ Line 97: / Line 96: @@
 |01:35
-| '''s equal to percentage s''', press '''Enter.'''
+| '''s equal to percentage s''',  '''Enter.'''  દબાવો.
 |-
 |01:41
-|Let us study the '''syslin Scilab command.'''
+| ચાલો '''syslin Scilab command.'''  નો અભ્યાસ કરીએ.
 |-
@@ Line 107: / Line 106: @@
 |01:44
-|Use the '''Scilab''' function''' ’syslin’ ''' to define the continuous time system.
+| '''continuous time system''' ને વ્યાખ્યાયિત કરવા માટે સાઈલેબ ફંક્શન '''syslin''' નો ઉપયોગ કરીએ છીએ.
 |-
@@ Line 117: / Line 116: @@
 |-
 |01:58
-|Use '''csim''' with '''step''' option, to obtain '''the step response''' and then plot the '''step response'''.
+|'''step response''' મેળવવા માટે  '''step''' ના સાથે '''csim''' ઉપયોગ કરો અને અને પછી ''' step response''' ને પ્લોટ કરો.
 |-