PoojaMoolya: Created page with "{|border=1 || '''Time''' || '''Narration''' |- || 00:01 || Welcome to the Spoken Tutorial on '''Inclined Plane'''. |- || 00:05 || In this tutorial we will learn to, |- || 00..."

2020-09-15T05:04:05Z

Created page with "{|border=1 || '''Time''' || '''Narration''' |- || 00:01 || Welcome to the Spoken Tutorial on '''Inclined Plane'''. |- || 00:05 || In this tutorial we will learn to, |- || 00..."

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{|border=1
|| '''Time'''
|| '''Narration'''
|-
|| 00:01
|| Welcome to the Spoken Tutorial on '''Inclined Plane'''.
|-
|| 00:05
|| In this tutorial we will learn to,

|-
|| 00:08
||Simulate the motion of a load on an inclined plane.

|-
|| 00:12
||Resolve the vector components using basic trigonometry.

|-
|| 00:17
||Calculate the vector components.

|-
|| 00:20
|| Here I am using,

'''Ubuntu Linux''' OS version 16.04 and '''Firefox Web Browser''' version 62.0.3
|-
|| 00:32
|| To follow this tutorial, learner should be familiar with '''Apps on Physics'''.

|-
|| 00:39
||For the pre-requisites tutorials please visit this site.

|-
|| 00:44
|| Let us define an inclined plane.

|-
|| 00:47
||An '''inclined plane''', is a flat supporting surface tilted at an angle.

|-
|| 00:52
||It has one end higher than the other.

|-
|| 00:56
||It is used for raising or lowering a load.

|-
|| 01:00
|| Use of an inclined plane provides greater mechanical advantage.

|-
|| 01:05
||Examples of an inclined plane are ramps, slides, stairs, water slides and others.

|-
|| 01:14
|| Use the given link to download the''' Apps.'''

|-
|| 01:18
|| I have already downloaded '''Apps on Physics '''to my '''Downloads''' folder.

|-
|| 01:23
||In this tutorial we will use,

'''Inclined Plane App'''.

|-
|| 01:29
|| After downloading, '''html5phen''' folder appears in the '''Downloads''' folder.
|-
||01:35
||Double click on '''html5phen''' folder.
|-
||01:39
|| Now double-click on the '''phen '''folder.

|-
|| 01:42
||In this folder, we see '''Apps''' in '''java script''' and '''htm''' format.

|-
|| 01:48
|| We will use the '''Apps''' with '''htm file''' format.

|-
|| 01:52
|| To open '''Inclined Plane''' press '''Ctrl, F''' keys simultaneously.

|-
|| 01:58
||In the search bar type '''inclined plane'''.
|-
|| 02:02
|| Right click on '''inclinedplane_en.htm''' file.

|-
|| 02:07
||Select the option '''Open With Firefox web Browser'''.

|-
|| 02:12
||'''Inclined Plane App''' opens in the '''browser'''.
|-
|| 02:16
|| This is the interface of '''Inclined plane'''.
|-
|| 02:20
|| The green panel shows different parameters that we can change.
|-
|| 02:25
|| '''Reset''' button on the top of the green panel helps to edit values.

|-
|| 02:30
||The yellow '''Start''' button is a '''toggle button''' for '''Start/Pause''' and '''Resume'''.

|-
|| 02:37
|| '''Slow motion''' check-box is used to observe the motion steadily.

|-
|| 02:42
|| Then we have '''Springscale''' and '''Force vectors''' radio buttons.

By default '''Springscale''' is selected.
|-
|| 02:52
|| Click on '''Start''' button.
|-
||02:55
||Notice that a load is pulled by the '''springscale'''.
|-
|| 02:59
|| Click on the '''Pause''' button.
|-
|| 03:02
|| Now select '''Force vectors radio button'''.
|-
||03:06
|| Observe that there are five arrows pointing in different directions.

|-
|| 03:11
|| We can change the values of: '''Angle of inclination''', '''Weight''' and '''Coefficient of friction''' in the white colour boxes.
|-
||03:20
||Note that these values can be changed within certain limits.
|-
|| 03:25
|| Click on '''Reset''' button.
|-
|| 03:28
|| Here we can change the '''Angle of inclination''' from 0 degrees to 90 degrees.

|-
|| 03:35
||Let’s change the '''Angle of inclination''' to 45 degrees and press '''Enter.'''
|-
|| 03:41
|| Now click on '''Start''' button.
|-
||03:44
|| When the load reaches the middle of the '''inclined plane '''click on '''Pause''' button.
|-
||03:50
|| Notice that the pink vector shows the force of gravity('''mg''').

|-
|| 03:54
||It tries to pull the load towards the center of the Earth.
|-
||03:59
||The blue and red vectors are the resolution vectors of gravity.
|-
||04:04
||The red vector is perpendicular to the surface of the '''inclined plane'''.
|-
||04:09
||The blue vector is parallel to the surface of the '''inclined plane'''.
|-
|| 04:15
|| If '''theta(θ)''' is 45 degrees, then this angle is 90 degrees.

As it is perpendicular to the surface of the earth.
|-
|| 04:23
||From the triangle’s geometry this angle would be '''(90-θ)'''.
|-
|| 04:29
|| To calculate the magnitude of the forces we need to know '''theta''' value.

|-
|| 04:35
||Now these two lines are parallel and if we assume that this line is a transversal line.

Then angle '''(90-θ)''' is equal this angle through interior angle property.

|-
|| 04:48
||Recall that red vector is perpendicular to the inclined plane.

|-
|| 04:53
||Here the angle would be 90 degrees.

|-
|| 04:57
||Let us assume this angle as '''x'''.

|-
|| 05:01
||So 90 minus '''theta''' plus 90 plus '''x''' equals to 180

Therefore, '''x''' equals to '''theta'''
|-
|| 05:12
|| Using basic trigonometry we can resolve the parallel and perpendicular components.

Consider this right angle triangle.

|-
|| 05:21
||Here the blue parallel component is equal to the black line.

|-
|| 05:26
|| Parallel force is '''Sin theta'''.

|-
|| 05:29
||'''Sin theta''' equals to '''F'''(parallel) upon '''mg'''.

|-
|| 05:34
||Let’s rearrange the equation.

'''F'''(parallel) equals to '''mg sin theta'''.

|-
|| 05:41
||Similarly we can resolve the perpendicular component.

|-
|| 05:46
||'''F'''(perpendicular) equals to '''mg cos theta'''.
|-
|| 05:50
|| Let us solve this numerical and verify the answers with the ones shown in the '''App'''.
|-
|| 05:57
|| Click on the '''Reset''' button to reset the '''App'''.
|-
|| 06:01
|| In the '''App''' change the values according to the numerical.

|-
|| 06:06
||First let us convert 1.02 '''Kg''' into '''Newton''' and enter the value in the '''Weight''' box.
|-
|| 06:14
|| Next change the '''Angle of inclination''' to 30 '''degrees''' and press '''Enter'''.
|-
|| 06:21
|| Now click on '''Start''' button.
|-
|| 06:24
|| Again click on '''Pause''' button when the load reaches the center of the inclined plane.
|-
|| 06:30
||Observe that the '''App''' has calculated the parameters.
|-
|| 06:36
||Next we will calculate using the formulae.
|-
|| 06:40
|| Calculated value of the parallel component is 4.99 '''Newton''' and that of normal component is 8.65 '''Newton'''.

|-
|| 06:51
||And the necessary force is equal to the parallel force but in the opposite direction.

|-
|| 06:59
||Let us compare the answers with the ones shown in the '''App'''.
|-
||07:04
||Observe that the calculated values are comparable to the measured values.
|-
|| 07:10
||Let's observe the effect of friction.
|-
|| 07:13
|| Click on the '''Reset''' button.
|-
|| 07:16
|| In the '''Coefficient of friction''' box type 0.5 and press '''Enter'''.
|-
|| 07:23
|| Click on the '''Start''' button.
|-
|| 07:26
|| When the load reaches the middle of the '''inclined plane''' click on '''Pause''' button.
|-
||07:31
||Notice that a black vector is added to the blue vector.

This vector represents '''Force of friction'''.
|-
||07:40
|| In the green panel '''Force of friction''' is measured as 4.3 '''Newton'''.
|-
|| 07:46
|| Notice that the '''Necessary force''' required to pull the load has changed to 9.3 '''Newton'''.

|-
|| 07:53
||This is because the total necessary force is, sum of parallel and frictional forces.

|-
||08:00
||As an assignment solve this numerical and compare your answer with the ones shown in the '''App'''.
|-
||08:08
||Let us summarise
|-
|| 08:10
|| Using this '''App''' we have Simulated the motion of a load on an inclined plane.

|-
|| 08:17
|| Resolve the vector components using basic trigonometry.

|-
|| 08:22
|| Calculated the vector components.
|-
|| 08:26
||These Apps are created by Walter-fendt and his team.

|-
|| 08:31
|| The video at the following link summarizes the Spoken Tutorial project.

Please download and watch it.
|-
|| 08:39
|| The '''Spoken Tutorial Project'''team, conducts workshops using spoken tutorials

and gives certificates. For more details, please write to us.
|-
|| 08:48
|| Please post your time queries on this forum

|-
||08:53
|| Spoken Tutorial Project is funded by MHRD, Government of India.
|-
|| 08:59
|| This is Himanshi Karwanje from IIT-Bombay.

Thank you for joining.
|-
|}

Apps-On-Physics/C2/Inclined-Plane/English-timed - Revision history

PoojaMoolya: Created page with "{|border=1 || '''Time''' || '''Narration''' |- || 00:01 || Welcome to the Spoken Tutorial on '''Inclined Plane'''. |- || 00:05 || In this tutorial we will learn to, |- || 00..."