Apps-On-Physics/C2/Inclined-Plane/English - Revision history

Karwanjehimanshi95 at 05:51, 5 June 2020

2020-06-05T05:51:30Z

Karwanjehimanshi95 at 05:50, 5 June 2020

2020-06-05T05:50:08Z

Karwanjehimanshi95 at 11:39, 8 July 2019

2019-07-08T11:39:37Z

Madhurig at 06:43, 13 June 2019

2019-06-13T06:43:58Z

Madhurig at 06:24, 13 June 2019

2019-06-13T06:24:34Z

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Karwanjehimanshi95 at 05:50, 13 June 2019

2019-06-13T05:50:09Z

Karwanjehimanshi95 at 05:45, 3 June 2019

2019-06-03T05:45:36Z

Karwanjehimanshi95 at 05:43, 3 June 2019

2019-06-03T05:43:19Z

Nancyvarkey at 04:29, 31 May 2019

2019-05-31T04:29:27Z

Karwanjehimanshi95 at 09:34, 29 May 2019

2019-05-29T09:34:10Z

@@ Line 69: / Line 69: @@
 |-
 || '''Slide Number 7'''
 ||In this tutorial we will use,

@@ Line 11: / Line 11: @@
 '''Learning objectives'''
-|| In this tutorial we will demonstrate,
+|| In this tutorial we will learn to,
 |-
 || '''Slide Number 3'''
@@ Line 34: / Line 39: @@
 |-
 || '''Slide Number 5'''
 '''Inclined Plane'''
@@ Line 69: / Line 66: @@
 || Point to the file in the downloads folder
 || I have already downloaded '''Apps on Physics '''to my '''Downloads''' folder.
 |-
 || Point to '''html5phen''' folder in the '''Downloads''' folder.
@@ Line 190: / Line 194: @@
 From the triangle’s geometry this angle would be '''(90-θ)'''.
 |-
-|| '''Slide Number 7'''
+|| '''Slide Number 8'''
 '''Resolution of vectors'''
@@ Line 209: / Line 213: @@
 Therefore, '''x''' equals to '''theta'''
 |-
-|| '''Slide Number 8'''
+|| '''Slide Number 9'''
 '''Resolution of Vectors'''
@@ Line 219: / Line 223: @@
 |-
-|| '''Slide Number 9'''
+|| '''Slide Number 10'''
 '''Resolution of Vector'''
@@ Line 234: / Line 238: @@
 '''F'''(perpendicular) equals to '''mg cos theta'''.
 |-
-|| '''Slide Number 10'''
+|| '''Slide Number 11'''
 '''Numerical'''
@@ Line 271: / Line 275: @@
 ||Next we will calculate using the formulae.
 |-
-|| '''Slide Number 11'''
+|| '''Slide Number 12'''
 '''Resolution of Gravity Forces'''
@@ Line 329: / Line 333: @@
 |-
-||'''Slide Number 12'''
+||'''Slide Number 13'''
 '''Assignment '''
@@ Line 343: / Line 347: @@
 ||Let us summarise
 |-
-|| '''Slide Number 12'''
+|| '''Slide Number 14'''
 '''Summary'''
 || Using this '''App''' we have
-* Demonstrated the motion of a load on an inclined plane with constant velocity.
-* Calculated the resolution of forces.
+* Simulated the motion of a load on an inclined plane.
 |-
-|| '''Slide Number 13'''
+|| '''Slide Number 15'''
 '''Acknowledgement'''
@@ Line 359: / Line 367: @@
 |-
-|| '''Slide Number 14'''
+|| '''Slide Number 16'''
 '''About Spoken Tutorial project'''.
@@ Line 366: / Line 374: @@
 Please download and watch it.
 |-
-|| '''Slide Number 15'''
+|| '''Slide Number 17'''
 '''Spoken Tutorial workshops.'''
@@ Line 377: / Line 385: @@
 For more details, please write to us.
 |-
-|| '''Slide Number 16'''
+|| '''Slide Number 18'''
 '''Forum for specific questions:'''
@@ Line 389: / Line 397: @@
 Explain your question briefly someone from our team will answer them.
 |-
-|| '''Slide Number 17'''
+|| '''Slide Number 19'''
 '''Acknowledgement'''

@@ Line 1: / Line 1: @@
 {|border=1
-|| '''Time'''
+|| '''Visual Cue'''
 || '''Narration'''
 |-

@@ Line 184: / Line 184: @@
 Sum of the interior angle of a triangle is 180 degrees.
-|| If '''theta (θ)''' is 45 degrees, then this angle is 90 degrees.
+|| If '''theta(θ)''' is 45 degrees, then this angle is 90 degrees.
 As it is perpendicular to the surface of the earth.
@@ Line 193: / Line 193: @@
 '''Resolution of vectors'''
-|| To calculate the magnitude of the forces we need to know theta value.
+|| To calculate the magnitude of the forces we need to know '''theta''' value.
 Now these two lines are parallel and if we assume that this line is a transversal line.
@@ Line 266: / Line 266: @@
 |-
 || Point to '''Normal force''', '''Parallel component''' and '''Necessary force'''.
-||Observe that the''' App''' has calculated the parameters.
+||Observe that the '''App''' has calculated the parameters.
 |-
 ||
@@ Line 326: / Line 326: @@
 || Notice that the '''Necessary force''' required to pull the load has changed to 9.3 '''N'''.
-This is because the total necessary force is, sum of the parallel and frictional forces.
+This is because the total necessary force is, sum of parallel and frictional forces.
 |-

@@ Line 150: / Line 150: @@
 |-
-|| Point to the white box for '''Angle of inclination, Weight, Coefficient of friction.'''
+|| Point to the white box for '''Angle of inclination''', '''Weight''', '''Coefficient of friction'''.
 || We can change the values of:
-'''Angle of inclination, Weight '''and '''Coefficient of friction '''in the white colour boxes.
+'''Angle of inclination, Weight'''and '''Coefficient of friction'''
 |-
 ||Highlight the line from the '''App'''.

@@ Line 312: / Line 312: @@
 <nowiki>= 8.65 N</nowiki>
-Necessary force = -F||<nowiki>
+Necessary force = -F||
 ||

@@ Line 247: / Line 247: @@
 || Parallel force is Sin theta.
-sin theta equals to F(parallel) upon mg
+sin theta equals to F(parallel) upon mg.
 Let’s rearrange the equation.
-F(parallel) equals to mg sin theta
+F(parallel) equals to mg sin theta.
 Similarly we can resolve the perpendicular component.
-F(perpendicular) equals to mg cos theta
+F(perpendicular) equals to mg cos theta.
 |-
 || '''Slide Number 10'''
@@ Line 268: / Line 268: @@
 ||
-Let us solve this numerical and verify the answer shown in the''' App'''.
+Let us solve this numerical and verify the answers with the ones shown in the''' App'''.
 |-
 || Click on the '''Reset''' button.
 || Click on the '''Reset''' button to reset the '''App'''.
 |-
-|| While editing show the conversion in a text-box.{1.02 / (divide by)9.8 we get as 10 '''N'''}
+|| 1.02 Kg = 10 N.
 Change the weight to 10 N.
@@ Line 279: / Line 279: @@
 || In the '''App''' change the values according to the numerical.
-First let us convert 1.02''' Kg '''into '''Newton''' and enter the value in the '''Weight''' box.
+First let us convert 1.02 '''Kg''' into '''Newton''' and enter the value in the '''Weight''' box.
 |-
-|| Change the '''Angle of inclination''' to 30 '''degrees''' and press '''Enter.'''
+|| Change the '''Angle of inclination''' to 30 '''degrees''' and press '''Enter'''.
 || Next change the '''Angle of inclination''' to 30 '''degrees''' and press '''Enter'''.
 |-
@@ Line 312: / Line 312: @@
 <nowiki>= 8.65 N</nowiki>
 ||
-Calculated value of the parallel component is 4.99 '''N '''and that of normal component is 8.65''' N '''
+Calculated value of the parallel component is 4.99 '''N '''and that of normal component is 8.65''' N '''.
 And the necessary force is equal to the parallel force but in the opposite direction.
@@ Line 321: / Line 322: @@
 Let us compare the answers with the ones shown in the '''App'''.
 |-
-|| Point to values of '''Normal force, Parallel component, and Necessary force.'''
+||Point to values of '''Normal force, Parallel component, and Necessary force'''.
 ||Observe that the calculated values are comparable to the measured values.
 |-
@@ Line 340: / Line 341: @@
 |-
 ||Move the cursor on the black vector.
-|| Notice that a black vector is added to the blue vector.
+||Notice that a black vector is added to the blue vector.
 This vector represents '''Force of friction.'''
@@ Line 382: / Line 383: @@
 '''Acknowledgement'''
-These Apps are created by Walter-fendt and his team.
+ These Apps are created by Walter-fendt and his team.
-|| These Apps are created by Walter-fendt and his team.
+||These Apps are created by Walter-fendt and his team.
 |-

@@ Line 22: / Line 22: @@
 || Here I am using,
-Ubuntu Linux OS version 16.04
+*'''Ubuntu Linux''' OS version 16.04
+*'''Firefox Web Browser''' version 62.0.3
 Firefox Web Browser version 62.0.3
 |-
 || '''Slide Number 4'''
@@ Line 34: / Line 33: @@
 For the pre-requisites tutorials please visit this site.
 |-
@@ Line 41: / Line 38: @@
 '''Learning Goals'''
-|| Using this App we will,
+|| Using this '''App''' we will,
 * Demonstrate the motion of a load on an inclined plane with constant velocity.
 * Calculate the resolution of forces.
 |-
@@ Line 63: / Line 59: @@
 Examples of an inclined plane are ramps, slides, stairs, water slides and others.
 |-
 || '''Slide Number 6'''
@@ Line 104: / Line 101: @@
-Select the option '''Open With Firefox web Browser''' option.
+Select the option '''Open With Firefox web Browser'''.
@@ Line 114: / Line 111: @@
-'''Inclined Plane App''' opens in the browser.
+'''Inclined Plane App''' opens in the '''browser'''.
 |-
 || Cursor on the interface.
@@ Line 141: / Line 138: @@
 |-
 ||Point to the block.
-||Notice that a load is pulled by the springscale.
+||Notice that a load is pulled by the '''springscale'''.
 |-
 || Click on the '''Pause '''button.
@@ Line 156: / Line 153: @@
 || We can change the values of:
-'''Angle of inclination, Weight '''and '''Coefficient of friction '''in the white colour boxes'''.'''
+'''Angle of inclination, Weight '''and '''Coefficient of friction '''in the white colour boxes.
 |-
 ||Highlight the line from the '''App'''.
@@ Line 223: / Line 220: @@
-Let us assume this angle as x
+Let us assume this angle as '''x'''.
-So '''90-θ+90+x=180'''
+So '''90 minus theta plus 90 plus x equals to 180'''
-'''x= θ'''
+Therefore, '''x equals to theta'''
 |-
 || '''Slide Number 8'''
@@ Line 250: / Line 247: @@
 || Parallel force is Sin theta.
-sin θ= F(parallel)/mg (base / hypotenuse)
+sin theta equals to F(parallel) upon mg
-let’s rearrange the equation.
+Let’s rearrange the equation.
-F(parallel)=mgsinθ
+F(parallel) equals to mg sin theta
 Similarly we can resolve the perpendicular component.
-F(perpendicular)=mgcosθ
+F(perpendicular) equals to mg cos theta
 |-
 || '''Slide Number 10'''
@@ Line 322: / Line 319: @@
 And the necessary force is equal to the parallel force but in the opposite direction.
-Let us compare the answers with the '''App'''.
+Let us compare the answers with the ones shown in the '''App'''.
 |-
 || Point to values of '''Normal force, Parallel component, and Necessary force.'''
-||Observe that the calculated values are comparable to the measured values by App.
+||Observe that the calculated values are comparable to the measured values.
 |-
 ||
@@ Line 334: / Line 331: @@
 |-
 || Enter 0.2 in the '''Coefficient of friction''' box.
-|| In the '''Coefficient of friction''' box type 0.5 and press Enter.
+|| In the '''Coefficient of friction''' box type 0.5 and press '''Enter'''.
 |-
 || Click on the '''Start '''button.
@@ Line 368: / Line 365: @@
 Calculate the necessary force to pull the load.
-||As an Assignment solve this numerical and compare your answer with the ones shown in the '''App'''.
+||As an assignment solve this numerical and compare your answer with the ones shown in the '''App'''.
 |-
 ||
-||Let us Summarise
+||Let us summarise
 |-
@@ Line 388: / Line 385: @@
 || These Apps are created by Walter-fendt and his team.
 |-
@@ Line 405: / Line 401: @@
-|| The&nbsp;'''Spoken Tutorial Project&nbsp;'''team,
+|| The '''Spoken Tutorial Project&nbsp;'''team,
 conducts workshops using spoken tutorials

@@ Line 66: / Line 66: @@
 || '''Slide Number 6'''
-Link for Apps on physics App
+Link for Apps on physics '''App'''
 '''https://www.walter-fendt.de/html5/phen/'''
@@ Line 92: / Line 92: @@
 In this folder, we see '''Apps''' in '''java script''' and '''htm '''format.
 |-
-|| Point to the '''htm''' formats Apps.
+|| Point to the '''htm''' formats '''Apps'''.
 || We will use the '''Apps''' with '''htm file''' format.
 |-
-|| Point to''' Inclined Plane Apps.'''
+|| Point to''' Inclined Plane Apps'''.
 || To open''' Inclined Plane''' press '''Ctrl, F''' keys simultaneously.
@@ Line 107: / Line 107: @@
-Cursor on the App.
+Cursor on the '''App'''.
 || Right click on '''inclinedplane_en.htm '''file.
@@ Line 130: / Line 130: @@
 || Point to the '''Slow motion.'''
 || '''Slow motion '''check-box is used to observe the motion steadily.
 |-
-|| Point to '''Springscale '''and '''Force vector'''
+|| Point to '''Springscale '''and '''Force vectors'''
-|| Then we have '''Springscale''' and '''Force vector '''radio buttons.
+|| Then we have '''Springscale''' and '''Force vectors '''radio buttons.
 By default '''Springscale''' is selected.
@@ Line 148: / Line 146: @@
 || Click on the '''Pause '''button.
 |-
-|| Click on the radio button of '''Force vector'''.
+|| Click on the radio button of '''Force vectors'''.
-|| Now select '''Force vector radio button'''.
+|| Now select '''Force vectors radio button'''.
 |-
 ||Point to the arrows.
 || Observe that there are five arrows pointing in different directions.
 |-
 || Point to the white box for '''Angle of inclination, Weight, Coefficient of friction.'''
 || We can change the values of:
-'''Angle of inclination, Weight '''and '''Coefficient of friction '''in the white colour box'''.'''
+'''Angle of inclination, Weight '''and '''Coefficient of friction '''in the white colour boxes'''.'''
 |-
-||Highlight the line from the App.
+||Highlight the line from the '''App'''.
 ||Note that these values can be changed within certain limits.
 |-
@@ Line 170: / Line 167: @@
 Change the '''Angle of inclination '''to 45 degrees and press '''Enter.'''
-|| Here we can change the A'''ngle of inclination''' from 0 degrees to 90 degrees.
+|| Here we can change the '''Angle of inclination''' from 0 degrees to 90 degrees.
@@ Line 178: / Line 175: @@
 || Now click on '''Start''' button.
 |-
-|| When it reaches in the middle of the incline plane click on '''Pause '''button.
+|| When it reaches in the middle of the inclined plane click on '''Pause '''button.
 || When the load reaches the middle of the '''inclined plane''' click on '''Pause '''button.
 |-
@@ Line 194: / Line 191: @@
 |-
 ||Point to blue vector and incline plane.
-||The blue vector is parallel to the surface of the '''inclined plane.'''
+||The blue vector is parallel to the surface of the '''inclined plane'''.
 |-
 || In the incline plane point to each angles(inclined plane png file.)
 Sum of the interior angle of a triangle is 180 degrees.
-−
-−
-Sum of the interior angle of a triangle is 180 degrees.(show as a text while editing)
 || If '''theta (θ) '''is 45 degrees, then this angle is 90 degrees.
@@ Line 238: / Line 232: @@
 '''Resolution of Vectors'''
@@ Line 282: / Line 274: @@
 |-
 || Click on the '''Reset''' button.
-|| Click on the '''Reset''' button to reset the App.
+|| Click on the '''Reset''' button to reset the '''App'''.
 |-
 || While editing show the conversion in a text-box.{1.02 / (divide by)9.8 we get as 10 '''N'''}
@@ Line 288: / Line 280: @@
 Change the weight to 10 N.
-|| In the App change the values according to the numerical.
+|| In the '''App''' change the values according to the numerical.
 First let us convert 1.02''' Kg '''into '''Newton''' and enter the value in the '''Weight''' box.
@@ Line 330: / Line 322: @@
 And the necessary force is equal to the parallel force but in the opposite direction.
-Let us compare the answers with the App.
+Let us compare the answers with the '''App'''.
 |-
 || Point to values of '''Normal force, Parallel component, and Necessary force.'''