Difference between revisions of "Python/C2/Using-Sage/Gujarati"
From Script | Spoken-Tutorial
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| − | |આપણે સીમાઓ, | + | |આપણે સીમાઓ, વિકલન, સંકલન, અને ટેયલરનો પોલિનોમિયલ વિષે જોઈશું. |
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| − | | | + | |એક દિશાથી બિંદુ મર્યાદિત કરવું શક્ય છે. ઉદાહરણ તરીકે, ચાલો 1/x at x=0 ની સીમા હકારાત્મક બાજુથી આગમન કરતી વખતે શોધીએ. |
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|1:23 | |1:23 | ||
| − | |lim | + | |lim કૌશ અંદર (1/x, x=0, dir='right') |
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| 1:32 | | 1:32 | ||
| − | | | + | |નકારાત્મક બાજુથી સીમા શોધવા માટે, આપણે કહીશું, |
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| − | | | + | | ચાલો સેજ ઉપયોગ કરીને, વિકલન કેવી રીતે શોધવું તે જોઈએ. |
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|1:51 | |1:51 | ||
| − | | | + | | આપણે exp(sin(x squared)) by x એક્ષપ્રેશનનું વિકલન x ના સંદર્ભમાં શોધીશું. |
|- | |- | ||
|2:11 | |2:11 | ||
| − | | | + | | તે માટે, આપણે પ્રથમ એક્ષપ્રેશન વ્યાખ્યાયિત કરીશું, અને પછી એક્સપ્રેશન નું વિકલન શોધવા માટે diff ફન્કશનનો ઉપયોગ કરીશું. |
|- | |- | ||
|2:21 | |2:21 | ||
| − | | | + | |તો આપણે ટાઇપ કરીશું, ('x) |
| − | f=exp of (sin x squared)/x | + | f=exp of (sin x squared)/x અને પછી ત્રીજી લાઈન માં ટાઇપ કરો, |
diff(f,x) | diff(f,x) | ||
Revision as of 15:52, 18 October 2013
| Timing | Narration |
|---|---|
| 0:00 | 'સેજના ઉપયોગ' પરના આ ટ્યુટોરીયલમાં સ્વાગત છે. |
| 0:02 | આ ટ્યુટોરીયલના અંતે, તમે
|
| 0:16 | આ ટ્યુટોરીયલ શરૂ કરો તે પહેલાં, અમારી સલાહ છે કે તમે "Getting started with Sage" પરનું ટ્યુટોરીયલ જુઓ. |
| 0:22 | ચાલો કેલક્યુલસ સાથે શરૂ કરીએ. |
| 0:24 | આપણે સીમાઓ, વિકલન, સંકલન, અને ટેયલરનો પોલિનોમિયલ વિષે જોઈશું. |
| 0:30 | આપણી સેજ નોટબુક ચાલી રહેલ છે. |
| 0:32 | જો તે ચાલી રહેલ નથી, તો તે કિસ્સામાં આ આદેશ વાપરી તે શરુ કરો, sage --notebook |
| 0:39 | તો sage ટાઇપ કરો અને નોટબુક સ્પષ્ટ કરો. |
| 0:45 | તો x =0 પાસે, ફન્કશન x ની સીમા sin(1/x) માં શોધવા માટે, આપણે ટાઇપ કરીશું, lim(x*sin(1/x),x=0) |
| 1:07 | ધાર્યા પ્રમાણે, આપણને સીમા 0 મળે છે. |
| 1:11 | એક દિશાથી બિંદુ મર્યાદિત કરવું શક્ય છે. ઉદાહરણ તરીકે, ચાલો 1/x at x=0 ની સીમા હકારાત્મક બાજુથી આગમન કરતી વખતે શોધીએ. |
| 1:23 | lim કૌશ અંદર (1/x, x=0, dir='right')
|
| 1:32 | નકારાત્મક બાજુથી સીમા શોધવા માટે, આપણે કહીશું, |
| 1:36 | lim(1/x, x=0, dir='left') |
| 1:45 | ચાલો સેજ ઉપયોગ કરીને, વિકલન કેવી રીતે શોધવું તે જોઈએ. |
| 1:51 | આપણે exp(sin(x squared)) by x એક્ષપ્રેશનનું વિકલન x ના સંદર્ભમાં શોધીશું. |
| 2:11 | તે માટે, આપણે પ્રથમ એક્ષપ્રેશન વ્યાખ્યાયિત કરીશું, અને પછી એક્સપ્રેશન નું વિકલન શોધવા માટે diff ફન્કશનનો ઉપયોગ કરીશું. |
| 2:21 | તો આપણે ટાઇપ કરીશું, ('x)
f=exp of (sin x squared)/x અને પછી ત્રીજી લાઈન માં ટાઇપ કરો, diff(f,x) |
| 2:44 | We can also obtain the partial differentiation of an expression w.r.t one of the variables. |
| 2:51 | Let us differentiate the expression exp(sin (y - x squared))/x w.r.t x and y. |
| 3:07 | that is with respect to x and y. |
| 3:10 | so you can type var('x y') |
| 3:15 | second line you can type f=exp(sin(y - x squared))by x |
| 3:26 | then you can type diff(f,x) then next line you can type diff(f,y) |
| 3:43 | Thus we get our partial differential solution. |
| 3:51 | Now, let us look at integration. |
| 3:53 | We shall use the expression obtained from the differentiation that we did before, diff(f, y)which gave us the expression ---e^(sin(-x squared + y)) multiplied by cos(-x squared plus y) by x |
| 4:15 | The integrate command is used to obtain the integral of an expression or function. |
| 4:21 | So you can type integrate(e^(sin(-x squared plus y))multiplied by cos(-x squared +y)by x,y) |
| 4:39 | As we can see,we get back the correct expression. |
| 4:44 | The minus sign being inside or outside the sin function doesn't change much. |
| 4:48 | Now, let us find the value of the integral between the limits 0 and pi/2. |
| 4:55 | So for that you can type integral(e^(sin(-x squared plus y))multiplied by cos(-x squared plus y) by x,y,0,pi/2) |
| 5:11 | Hence we got our solution for definite integration. |
| 5:15 | Now, let us see how to obtain the Taylor expansion of an expression using sage. |
| 5:20 | Let us obtain the Taylor expansion of (x + 1) raised to n up to degree 4 about 0. |
| 5:27 | So for that you can type var of ('x n') then type taylor within brackets((x+1) raised to n,x,0,4) |
| 5:42 | We easily got the Taylor expansion,using the taylor function taylor() function. |
| 5:49 | So this brings us to the end of the features of Sage for Calculus, that we will be looking at. |
| 5:56 | For more, look at the Calculus quick-ref from the Sage Wiki. |
| 6:03 | Next let us move on to Matrix Algebra. |
| 6:07 | Let us begin with solving the equation Ax = v, where A is the matrix matrix ([[1,2], [3,4]]) and v is the vector vector ([1,2]). |
| 6:19 | So, to solve the equation,Ax = v we simply say |
| 6:23 | A=matrix ([1,2] comma [3,4]) then v is equal to vector([1,2]) |
| 6:35 | then x=A dot solve underscore right(v) |
| 6:50 | then you have to type |
| 7:01 | then type x |
| 7:07 | To solve an equation, xA = v we simply say |
| 7:14 | x=A dot solve underscore left(v) |
| 7:25 | then type x |
| 7:32 | The left and right here, denote the position of A, relative to x. |
| 7:36 | Now, let us look at Graph Theory in Sage. |
| 7:39 | We shall look at some ways to create graphs and some of the graph families available in Sage. |
| 7:45 | The simplest way to define an arbitrary graph is to use a dictionary of lists. |
| 7:49 | We create a simple graph by using the Graph() function. |
| 7:53 | So G=Graph({0:[1,2,3], 2:[4]}) and hit shift enter |
| 8:13 | To view the visualization of the graph, we say |
| 8:17 | G.show() |
| 8:24 | Similarly, we can obtain a directed graph using the DiGraph function. |
| 8:31 | So ,you have to type G=DiGraph that is D and G are capital ({0 colon [1,2,3],2 colon[4]}) and hit shift enter. |
| 8:59 | Sage also provides a lot of graph families which can be viewed by typing graph.tab. |
| 9:04 | Let us obtain a complete graph with 5 vertices and then show the graph. |
| 9:09 | So you can type there G=graphs dot Complete Graph(5) then type G dot show() |
| 9:28 | Sage provides other functions for Number theory and Combinatorics. |
| 9:35 | Let's have a glimpse of a few of them. |
| 9:42 | So prime_range gives primes in the range 100 to 200. |
| 9:46 | So you can type there prime_range within brackets 100,200. |
| 9:58 | is_prime checks if 1999 is a prime number or not. |
| 10:05 | So for that you can type if_prime of (1999) and hit shift enter. |
| 10:13 | So you will get the answer. |
| 10:15 | factor(2001) gives the factorized form of 2001. |
| 10:20 | So to see that you can type factor(2001) and hit shift enter. |
| 10:33 | So you can see the value in the output. |
| 10:36 | So the Permutations() gives the permutations of [1, 2, 3, 4] |
| 10:43 | So for that you can type C=Permutations([1,2,3,4]) and next you can type C.list() |
| 10:57 | And the Combinations() gives all the combinations of [1, 2, 3, 4] |
| 11:02 | For that you can type C= Combinations([1,2,3,4]) and type C dot list() |
| 11:17 | So now you can see the solution displayed |
| 11:26 | This brings us to the end of the tutorial. |
| 11:29 | So In this tutorial, we have learnt to, |
| 11:32 | 1. Use functions for calculus like -- - lim()-- to find out the limit of a function - diff()-- to find out the differentiation of an expression - integrate()-- to integrate over an expression - integral()-- to find out the definite integral of an expression by specifying the limits br |
| 11:52 | solve()-- to solve a function, relative to it's position. |
| 11:56 | then create both a simple graph and a directed graph, using the functions graph and digraph respectively. |
| 12:02 | then use functions for number theory. |
| 12:04 | So for eg: - primes_range()-- function to find out the prime numbers within the specified range. |
| 12:11 | then factor()-- function to find out the factorized form of the specified number. |
| 12:15 | Permutations(), Combinations()-- to obtain the required permutation and combinations for the given set of values. |
| 12:22 | So here are some self assessment questions for you to solve |
| 12:25 | 1. How do you find the limit of the function x/sin(x) as x tends to 0 from the negative side. |
| 12:32 | 2. List all the primes between 2009 and 2900 |
| 12:37 | 3. Solve the system of linear equations x-2y+3z = 7 2x+3y-z = 5 x+2y+4z = 9 |
| 12:57 | So now we can look at the answers, |
| 13:02 | 1. To find out the limit of an expression from the negative side,we add an argument dir="left" as |
| 13:09 | lim of(x/sin(x), x=0, dir="left") |
| 13:19 | 2. The prime numbers from 2009 and 2900 can be obtained as,
prime_range(2009, 2901) |
| 13:32 | 3. We shall first write the equations in matrix form and then use the solve() function |
| 13:39 | So you can type A = Matrix of within brackets([[1, -2, 3] comma [2, 3, -1] comma [1, 2, 4]]) |
| 13:48 | b = vector within brackets([7, 5, 9]) |
| 13:52 | then x = A dot solve_right(b) |
| 13:58 | Then type x so that you can view the output of x. |
| 14:03 | So we hope that you have enjoyed this tutorial and found it useful. |
| 14:06 | Thank you! |
